返回阵列方法的奇怪输出

Question

以下是工作代码的“主要”正文：

public class ArrayFunHouse
{
    //instance variables and constructors could be used, but are not really needed

    //getSum() will return the sum of the numbers from start to stop, not including stop
    public static int getSum(int[] numArray, int start, int stop)
    {
        int sum = 0;

        for(int count = start; count <= stop; count++) {
            sum += numArray[count];
        }
        return sum;
    }

    //getCount() will return number of times val is present
    public static int getCount(int[] numArray, int val)
    {
        int present = 0;

        for(int count = 0; count < numArray.length; count++) {
            if(numArray[count] == val) {
                present++;
            }
        }
        return present;
    }

    public static int[] removeVal(int[] numArray, int val)
    {
        int[] removal = new int[numArray.length - getCount(numArray, val)];
        int arbitrary = 0;

        for(int count = 0; count < removal.length; count++) {
            if(numArray[count] == val) {
                arbitrary++;
            } else {
                removal[count - arbitrary] = numArray[count];
            }
        }

        return removal;
    }
}

.

和跑步者类：

import java.util.Arrays;

public class ArrayFunHouseRunner
{
public static void main( String args[] )
{
    int[] one = {4,10,0,1,7,6,5,3,2,9};

    System.out.println(Arrays.toString(one));
    System.out.println("sum of spots 3-6  =  " + ArrayFunHouse.getSum(one,3,6));
    System.out.println("sum of spots 2-9  =  " + ArrayFunHouse.getSum(one,2,9));
    System.out.println("# of 4s  =  " + ArrayFunHouse.getCount(one,4));
    System.out.println("# of 9s  =  " + ArrayFunHouse.getCount(one,9));
    System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one,7));
    System.out.println("new array with all 7s removed = "+     ArrayFunHouse.removeVal(one, 7));


}
}

.

返回一些我希望尝试在没有ToString的情况下打印类的东西，即：

[4, 10, 0, 1, 7, 6, 5, 3, 2, 9]
sum of spots 3-6  =  19
sum of spots 2-9  =  33
number of 4s  =  1
number of 9s  =  1
number of 7s  =  1
new array with all 7s removed = [I@56f7ce53

.

我知道我在跑步者中正确地打电话，没有太多搞砸了，无法确定问题，任何建议？

最终编辑：那就令人尴尬。问题实际上是跑步者，而不是叫阵列。

Answer 1

用

打印

System.out.println(Arrays.toString(array));

.

如果您的数组中有数组。

System.out.println(Arrays.deepToString(array));

.

Answer 2

正如您所说，您正在打印返回的数组的toString()。但是，在Java中，阵列不覆盖生成扫描仪，因此您得到的输出。 而不是只打印返回的值，请使用toString()打印它的值 - 这应该为您提供所需的输出。