UITableview 搜索解析 - 没有结果
-
20-12-2019 - |
题
我正在尝试使用 UISearch
栏能够找到特定人员的所有对象。我已将其设置为每个 PFUser
或者用户在主对象中有一个名称对象 points
. 。当我尝试查找用户和对象时,什么也没有出现,但在 NSLogs 中我获得了所有信息。我认为我的问题在于 cellForRowAtIndexPath
, ,但我不知道为什么!
首先我查询:
- (PFQuery *)queryForTable {
PFQuery *query = [PFQuery queryWithClassName:@"points"];
// The key of the PFObject to display in the label of the default cell style
//self.textKey = @"opponent";
// Uncomment the following line to specify the key of a PFFile on the PFObject to display in the imageView of the default cell style
// self.imageKey = @"image";
// Whether the built-in pull-to-refresh is enabled
self.pullToRefreshEnabled = YES;
// Whether the built-in pagination is enabled
self.paginationEnabled = NO;
// The number of objects to show per page
self.objectsPerPage = 50;
//where you set the username to the specific user to get only this user's post.
// If no objects are loaded in memory, we look to the cache first to fill the table
// and then subsequently do a query against the network.
if (self.objects.count == 0) {
query.cachePolicy = kPFCachePolicyCacheThenNetwork;
}
[query orderByDescending:@"createdAt"];
return query;
}
我放置我的酒吧:
-(void)viewDidAppear:(BOOL)animated{
self.searchBar = [[UISearchBar alloc] initWithFrame:CGRectMake(0, 0, self.view.frame.size.width, 44)];
self.tableView.tableHeaderView = self.searchBar;
self.searchController = [[UISearchDisplayController alloc] initWithSearchBar:self.searchBar contentsController:self];
self.searchController.searchResultsDataSource = self;
self.searchController.searchResultsDelegate = self;
self.searchController.delegate = self;
//CGPoint offset = CGPointMake(0, self.searchBar.frame.size.height);
//self.tableView.contentOffset = offset;
self.searchResults = [NSMutableArray array];
}
过滤结果:
-(void)filterResults:(NSString *)searchTerm {
[self.searchResults removeAllObjects];
PFQuery *query = [PFQuery queryWithClassName: @"points"];
[query whereKeyExists:@"name"]; //this is based on whatever query you are trying to accomplish
[query whereKeyExists:@"opponent"]; //this is based on whatever query you are trying to accomplish
[query whereKey:@"name" containsString:searchTerm];
NSArray *results = [query findObjects];
NSLog(@"%@", results);
NSLog(@"%u", results.count);
[self.searchResults addObjectsFromArray:results];
}
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString {
[self filterResults:searchString];
return YES;
}
Counting The Objects:
-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
if (tableView == self.tableView) {
//if (tableView == self.searchDisplayController.searchResultsTableView) {
return self.objects.count;
} else {
return self.searchResults.count;
}
}
- (CGFloat)tableView:(UITableView *)tableView heightForRowAtIndexPath:(NSIndexPath *)indexPath
{
return 110;
}
试图展示这一切!:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath object:(PFObject *)object {
// If you want a custom cell, create a new subclass of PFTableViewCell, set the cell identifier in IB, then change this string to match
// You can access any IBOutlets declared in the .h file from here and set the values accordingly
// "Cell" is the default cell identifier in a new Master-Detail Project
static NSString *CellIdentifier = @"celltag";
UITableViewCell *cell = (UITableViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
}
if (tableView != self.searchDisplayController.searchResultsTableView) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
}
if ([tableView isEqual:self.searchDisplayController.searchResultsTableView]) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
}
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
return cell;
}
解决方案
你的也有很多错误 cellForRowAtIndexPath
方法。
(1) 它包含一个奇怪的条件句。
A。 首先,您将指针与 !=
操作员:
if (tableView != self.searchDisplayController.searchResultsTableView)
但是然后你使用比较对象 isEqual
if ([tableView isEqual:self.searchDisplayController.searchResultsTableView])
虽然这两种方法都足够了,而且这个条件在技术上应该可行,但我最好保持一致;并且由于 tableView 中 cellForRowAtIndexPath
保存对指针的引用,使用 == 或 != 运算符不仅足够,而且更快。
b. 以这种方式使用两个 if 也是很糟糕的形式,因为你有 if
两个选项的声明。相反,我建议使用 if-else 语句:
if (tableView != self.searchDisplayController.searchResultsTableView) {
...
} else {
...
}
return cell;
C。 按照目前的情况,你的条件是完全没有必要的。您在两个条件块中都有相同的代码,甚至在条件块之后也有相同的代码!因此,就目前情况而言,您可以删除这两个 if 语句,因为 if 语句之外的最后一个代码是唯一真正执行的代码。
(2)但是你 做 事实上需要一个条件,即使你当前的条件是多余的。
关于为什么在使用您指定的代码时表格不会改变的最主要问题:
由于您使用的是 Parse cellForRowAtIndexPath
方法,行数据正在填充来自的信息 - (PFQuery *)queryForTable
, ,因此当您当前编写代码时,对象将使用此查询的结果填充:
PFQuery *query = [PFQuery queryWithClassName:@"points"];
当您不进行搜索时,可以使用从此查询返回的 Parse PFObject 参数,但使用 self.searchResults 数组当前索引处的对象,即 [self.searchResults objectAtIndex:indexPath.row]
, ,当您搜索时,例如:
if (tableView != self.searchDisplayController.searchResultsTableView) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"], [object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
} else {
PFObject *searchResult = [self.searchResults objectAtIndex:indexPath.row];
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [searchResult objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[searchResult objectForKey:@"goals"], [searchResult objectForKey:@"assists"], [searchResult objectForKey:@"totalpoints"], [searchResult objectForKey:@"plusminus"], [searchResult objectForKey:@"hits"], [return cell; objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [searchResult objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [searchResult objectForKey:@"name"];
}
return cell;