Python中的文本清理

Question

我是Python的新手，无法找到删除无用文本的方法。主要目的是保留我想要的单词并删除所有其余部分。在这个阶段，我可以检查我的 in_数据 找到我想要的词。如果 判决。查找(wordToCheck) 是积极的，然后保持它。该 in_数据 是每行的句子，但当前输出是每行的一个单词。我想要的是保留格式，在每行中找到单词并删除其余部分。

import Orange
import orange

word = ['roaming','overseas','samsung']
out_data = []

for i in range(len(in_data)):
    for j in range(len(word)):
        sentence = str(in_data[i][0])
        wordToCheck = word[j]
        if(sentence.find(wordToCheck) >= 0):
            print wordToCheck

输出

roaming
overseas
roaming
overseas
roaming
overseas
samsung
samsung

该 in_数据 句子是这样的吗？

contacted vodafone about going overseas and asked about roaming charges. The customer support officer says there isn't a charge but while checking my usage overseas.

我期望看到输出就像

overseas roaming overseas

Answer 1

您可以为此使用regex:

>>> import re
>>> word = ['roaming','overseas','samsung']
>>> s =  "Contacted vodafone about going overseas and asked about roaming charges. The customer support officer says there isn't a charge but while checking my usage overseas."
>>> pattern = r'|'.join(map(re.escape, word))
>>> re.findall(pattern, s)
['overseas', 'roaming', 'overseas']
>>> ' '.join(_)
'overseas roaming overseas'

非正则表达式的方法是使用 str.join 与 str.strip 和生成器表达式。需要使用strip()调用来消除标点符号，例如 '.', ',' 等。

>>> from string import punctuation
>>> ' '.join(y for y in (x.strip(punctuation) for x in s.split()) if y in word)
'overseas roaming overseas'

Answer 2

这是一种更简单的方式：

>>> import re
>>> i
"Contacted vodafone about going overseas and asked about roaming charges. The customer support officer says there isn't a charge but while checking my usage overseas."
>>> words
['roaming', 'overseas', 'samsung']
>>> [w for w in re.findall(r"[\w']+", i) if w in words]
['overseas', 'roaming', 'overseas']

.

Answer 3

你可以做得更简单，像这样:

for w in in_data.split():
    if w in word:
        print w

在这里，我们首先分开 in_data 通过空格，它返回一个单词列表。然后，我们循环遍历in数据中的每个单词，并检查该单词是否等于您要查找的单词之一。如果是的话，我们就打印出来。

而且，为了更快地查找，请 word-列出一组，而不是。快得多。

此外，如果要处理标点符号和符号，则需要使用正则表达式或检查字符串中的所有字符是否都是字母。所以，要获得你想要的输出:

import string
in_words = ('roaming','overseas','samsung')
out_words = []

for w in in_data.split():
    w = "".join([c for c in w if c in string.letters])
    if w in in_words:
        out_words.append(w)
" ".join(out_words)

Answer 4

使用拆分的答案将落在标点符号上。你需要用正则表达式分解单词。

import re

in_data = "contacted vodafone about going overseas and asked about roaming charges. The customer support officer says there isn't a charge but while checking my usage overseas."

word = ['roaming','overseas','samsung']
out_data = []

word_re = re.compile(r'[^\w\']+')
for check_word in word_re.split(in_data):
  if check_word in word:
    print check_word

.