我如何将我的新对象数据转换为从Firebase从Firebase中检索到JSON表单之前

Question

我刚刚用我的yeoman，Angularjs App设置了我的Firebase，AngularFire数据库。我用来硬编码我的数据，然后是so

$scope.data = [
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    ...
    ...
    More Data...
    ...
    ...
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... }
]

.

当我将上面的数据上传到我的Firebase数据库时，我必须拥有有效的JSON数据形式，因此我将其转换为此

[
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    ...
    ...
]

.

是有效的JSON格式。现在，当我控制台时（Firebaseref），我的数据正在下面的表单中检索。这正是我在Google Chrome控制台中所看到的。

Object {$bind: function, $add: function, $save: function, $set: function, $transaction: function…}
    0: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    1: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    2: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    ...
    ...
    ...More Data...
    ...
    ...

.

如何将我的新对象数据转换为从Firebase检索到与我之前相同的形式？

这是两者之间的主要区别的图片。我收到的Firebase数据似乎是一个具有多个对象的对象，并且之前我想要/使用的数据是多个对象的数组。

Answer 1

根据此URL：对象到数组 - 快速转换

需要将Firebase对象分配给变量：

$scope.firebaseObj

.

然后您可以将其填充到$ scope.data对象：

$scope.data = [];
 for (var i = 0; i < $scope.firebaseObj.length; i++) {
      $scope.data[i]['name']= $scope.firebaseObj[i].name;
      $scope.data[i]['description']= $scope.firebaseObj[i].description;
      $scope.data[i]['type'] =  $scope.firebaseObj[i].type;
      $scope.data[i]['etc1'] =  $scope.firebaseObj[i].etc1;
      $scope.data[i]['etc12'] =  $scope.firebaseObj[i].etc2;
      .
      .
      . 
 }

.

如果JSON中的每个元素具有相同的属性

，则只能工作