使用嵌套形式实现多个表继承时，“无法批准受保护的属性”

Question

嗨，我正在尝试在我的应用程序中实现MTI。我有一个人模型和2个模型继承了它：客户和团队管理。在创建团队成员时，我想保存到数据库Vallues的人（名字和姓氏，电子邮件等）和团队成员（体验级别，团队类型，如果领先或不行）。我在我的团队成员表格中使用嵌套属性表单，我嵌套了人员字段。不幸的是，我在尝试保存时获得“无法批判受保护的属性：人”错误。有谁可以告诉我如何解决这个问题？谢谢！ 型号：

更新了Teammember类，但仍然是相同的错误 也尝试过people_attributes和persons_attributes，这些都不是这些工作

class TeamMember < ActiveRecord::Base
  has_many :project_team_members
  has_many :projects, through: :project_team_members
  has_one :person, as: :profile, dependent: :destroy
  accepts_nested_attributes_for :person
  attr_accessible :person_attributes, :experience_level, :lead, :qualification, :team
end

class Person < ActiveRecord::Base
  belongs_to :company
  belongs_to :profile, polymorphic: true
  attr_accessible :email, :first_name, :last_name, :phone_number, :profile_id,     :profile_type
end

.

控制器如下：

class TeamMembersController < ApplicationController
  def create
    person = Person.create! { |p| p.profile = TeamMember.create!(params[:team_member]) }
    redirect_to root_url
  end

.

和视图：

<%= form_for(@team_member) do |f| %>
  <%= f.fields_for :person do |ff| %>
    <div>
      <%= ff.label :first_name %>
      <%= ff.text_field :first_name %>
    </div>
    <div>
      <%= ff.label :last_name %>
      <%= ff.text_field :last_name %>
    </div>
    <div>
      <%= ff.label :phone_number %>
      <%= ff.text_field :phone_number %>
    </div>
    <div>
      <%= ff.label :email %>
      <%= ff.text_field :email %>
    </div>
    <div>
      <%= ff.label :company_id %>
      <%= ff.text_field :company_id %>
    </div>
<% end %>
<div class="field">
  <%= f.label :team %><br />
  <%= f.text_field :team %>
</div>
<div class="field">
  <%= f.label :experience_level %><br />
  <%= f.text_field :experience_level %>
</div>
<div class="field">
  <%= f.label :qualification %><br />
  <%= f.text_field :qualification %>
</div>
<div class="field">
  <%= f.label :lead %><br />
  <%= f.check_box :lead %>
</div>
  <div class="actions">
<%= f.submit %>
</div>

.

更新的TeammembersController（通过Tiago的礼貌，解决方案）

def new
  @team_member = TeamMember.new
  @team_member.build_person

  respond_to do |format|
    format.html # new.html.erb
    format.json { render json: @team_member }
  end
end

def create
  @team_member = TeamMember.create!(params[:team_member])
  redirect_to root_url
end

.

Answer 1

以嵌套形式的质量分配属性，您需要指定：

class TeamMember < ActiveRecord::Base
  has_many :project_team_members
  has_many :projects, through: :project_team_members
  has_one :person, as: :profile, dependent: :destroy
  :experience_level, :lead, :qualification, :team #what is this line doing??
  accepts_nested_attributes_for :person      
  attr_accessible :person_attributes    
end

.

编辑：

在您需要构建人的表单之前调用的动作中。喜欢：

@team_member = TeamMember.new
@team_member.build_person

.

然后你将有一个与@team_member关联的人（不持久）。