我正在尝试制作一个程序,为抛硬币生成“赢”或“输”, 输出 将数据写入文件,并读取该数据以计算 平均的, ,但我得到了'java.util.NoSuchElementException' 错误. 。我不完全确定为什么我会得到这个..非常感谢您的帮助。

import java.util.Scanner;
import java.util.Random;
import java.io.IOException;
import java.io.PrintWriter;
import java.io.File;
public class BottleCapPrize
{
    public static void main(String [] args) throws IOException
    {            
        int random;
        int loop = 1;
        double trials = 0;
        double winCounter = 0;
        double average;
        String token = "";

        //

        Scanner in = new Scanner(System.in);
        Random rand = new Random();
        PrintWriter outFile = new PrintWriter (new File("MonteCarloMethod.txt"));

        //User Input Trials
        System.out.print("Number of trials: ");
        trials = in.nextInt();

        //For loop (random, and print to file)
        average = 0;
        for(loop = 1; loop <= trials; loop++)
        {
            random = rand.nextInt(5);
            if(random == 1)
            {
                outFile.println("Trial: " + loop + " WIN!");
            }
            outFile.println("Trial: " + loop + " LOSE");
        }

        outFile.close();

        //read output 
        File fileName = new File("MonteCarloMethod.txt");
        Scanner inFile = new Scanner(fileName);
        while (inFile.hasNextLine())
        {
            token = inFile.next();
            if (token.equalsIgnoreCase( "WIN!" ))
            {
                winCounter++;
            }

        }

        //average and print average
        average = winCounter / trials * 100;
        outFile.println("Average number of caps to win: " + average);
        System.out.println("Average number of caps to win: " + average);

        }
    }
有帮助吗?

解决方案

改变 inFile.next()inFile.nextLine()

另外,你会想要改变 if (token.equalsIgnoreCase( "WIN!" ))if(token.contains("WIN!")) 否则它永远不会通过(.equals 检查整行是否是“赢!”只有“赢!”, .contains 检查该线是否有“获胜!”在里面。)

其他提示

在您测试的阅读循环中 inFile.hasNextLine(), ,但尝试通过以下方式获取下一个令牌 inFile.next(). 。然而,有下一行并不一定意味着有下一个标记。

要么改变 hasNextLine()hasNext(), ,或改变 next()nextLine() (前提是所有标记都位于单独的行上)。

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