题
这是为我正在研究的脚本。它应该运行以下循环的.exe文件。 (顺便说一下,不确定它是否可见,而是对EL('90','52.6223',...)在循环外部,其余的嵌套环在循环之外),我不确定订购是否正确或没有什么。同样,当.exe文件运行时,它会吐出一些内容,我需要在屏幕上打印一条一行(因此,您可以看到Aspecificlinfe = ...)。任何有用的答案都很棒!
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
comstring = os.path.join('Path where .exe file is')
comstring = os.path.normpath(comstring)
comstring = '"' + comstring + '"'
comstringfull = comstring + ' -el ' + str(el) + ' -n ' + str(z)
print 'The python program is running this command with the shell:'
print comstring + '\n'
process = Popen(comstring,shell=True,stderr=STDOUT,stdout=PIPE)
outputstring = myprocesscommunicate()
print 'The command shell returned the following back to python:'
print outputstring[0]
AspecificLine=linecache.getline(' ??filename?? ', # ??
sys.stderr.write('az', 'el', 'AREA' ) # ??
解决方案
使用 shell=True
是错误的,因为那不必要的刺激了壳。
相反,这样做:
for el in ('90.','52.62263.','26.5651.','10.8123.'):
if el == '90.':
z = ('0.')
elif el == '52.62263.':
z = ('0.', '72.', '144.', '216.', '288.')
elif el == '26.5651':
z = ('324.', '36.', '108.', '180.', '252.')
else el == '10.8123':
z = ('288.', '0.', '72.', '144.', '216.')
for az in z:
exepath = os.path.join('Path where .exe file is')
exepath = os.path.normpath(comstring)
cmd = [exepath, '-el', str(el), '-n', str(z)]
print 'The python program is running this command:'
print cmd
process = Popen(cmd, stderr=STDOUT, stdout=PIPE)
outputstring = process.communicate()[0]
print 'The command returned the following back to python:'
print outputstring
outputlist = outputstring.splitlines()
AspecificLine = outputlist[22] # get some specific line. 23?
print AspecificLine
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