在Android中的两个地理位点之间的距离和轴承

Question

我正在尝试计算两个地质点之间的距离和轴承。这是我在互联网上找到的代码，但它返回不同的值。

double currentLat = 51.43376;
    double currentLng = -2.86221;

    double destLat = 51.43503; 
    double destLng = -2.86869;

    final float[] results= new float[3];
    Location.distanceBetween(currentLat, currentLng, destLat, destLng, results);
    System.out.println("GPS" + "results[0]: " + results[0]);
    System.out.println("GPS" + "results[1]: " + results[1]);
    System.out.println("GPS" + "results[2]: " + results[2]);


    Location here = new Location("Current");
    here.setLatitude(currentLat);
    here.setLatitude(currentLng);

    Location dest = new Location("Destination2");
    dest.setLatitude(destLat);
    dest.setLongitude(destLng);


    System.out.println("GPS" + "Bearing to dest: " + here.bearingTo(dest));
    System.out.println("GPS" + "Distance to dest: " + here.distanceTo(dest));

.

logcat：

04-13 17:46:13.056: I/System.out(1349): GPSresults[0]: 472.2533
04-13 17:46:13.056: I/System.out(1349): GPSresults[1]: -72.5882
04-13 17:46:13.066: I/System.out(1349): GPSresults[2]: -72.59327
04-13 17:46:13.066: I/System.out(1349): GPSBearing to dest: -2.2131138
04-13 17:46:13.066: I/System.out(1349): GPSDistance to dest: 6023135.0

.

所以任何人都可以帮助我解决这些方法，并告诉我哪一个是正确的使用。 谢谢

Answer 1

在代码中：

Location here = new Location("Current");
here.setLatitude(currentLat);
here.setLatitude(currentLng);

.

你的纬度是两次。纠正，它给出了绝对正确的结果。