我的架构看起来像这样:

CREATE TABLE plans (
    id SERIAL PRIMARY KEY,
    description text
);

CREATE TABLE projects (
    id SERIAL PRIMARY KEY,
    project_id character varying(240) UNIQUE,
    plan_id integer REFERENCES plans(id) ON DELETE CASCADE
);

我想按照以下方式进行 Storm 查询

plan = store.find(Plan, Plan.project_id == "alpha")
# should translate to something like
# SELECT p.* from plans p LEFT JOIN projects proj ON p.id = proj.plan_id
#     WHERE proj.project_id = 'alpha';

(注意 projects.plan_id 并不独特。)

我该如何设置?

有帮助吗?

解决方案

对于给定的 SQL,没有太多理由使用左连接,因为您的 where 子句不会匹配任何没有相应项目的行。您可以通过以下方式获得结果:

result = store.find(Plan, Plan.id == Project.plan_id, Project.project_id == "alpha")

这将为您提供一个 ResultSet 对象。考虑到您的架构,您似乎需要一行,因此您可以通过以下方式访问它:

plan = result.one()

或者将它们连接在一起:

plan = store.find(Plan, Plan.id == Project.plan_id, Project.project_id == "alpha").one()

如果您确实需要进行左连接,其语法将如下所示:

result = store.using(LeftJoin(Plan, Project, Plan.id == Project.plan_id)).find(
    Plan, Project.project_id == "alpha")
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