使用GTK/GDK获取Pango渲染的像素

StackOverflow https://stackoverflow.com/questions/1830589

  •  11-09-2019
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题

我试图获取 Pango 使用给定字符（在本例中为字母“T”）渲染的位图。我认为这应该可行，但它只是打印出垃圾..

在这段代码中， gtk_window 已经初始化为 GTK 窗口。

int width, height;
PangoLayout *layout = gtk_widget_create_pango_layout(gtk_window, "T");
PangoFontDescription *fontdesc = pango_font_description_from_string("Terminus 12");
pango_layout_set_font_description (layout, fontdesc);
pango_layout_get_pixel_size (layout, &width, &height);

GdkPixmap *temp_pixmap = gdk_pixmap_new(NULL, width, height, 24) ;
GdkGC *gc = gdk_gc_new(temp_pixmap);
gdk_draw_layout( temp_pixmap, gc, 0, 0, layout) ;

GdkColormap *cmap = gdk_colormap_get_system() ;
GdkPixbuf *temp_pixbuf = gdk_pixbuf_get_from_drawable(NULL, temp_pixmap,
                                       cmap, 0, 0, 0, 0, width, height);

int n_channels = gdk_pixbuf_get_n_channels (temp_pixbuf);
int rowstride = gdk_pixbuf_get_rowstride(temp_pixbuf);
guchar *pixels = gdk_pixbuf_get_pixels(temp_pixbuf);

int i,j;
for (j=0; j<height; j++) {
    for (i=0; i<(width*n_channels); i++) {
        printf("%02x ",
               *(pixels + i + j*rowstride));
    }
    printf("\n");
}

每次的输出都不同，但举个例子：

dd 24 f8 dd 24 f8 8f 28 28 8f 28 28 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 fc 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
ef 14 ce 00 00 00 d0 00 20 00 00 00 ef 02 02 d0 00 01 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 fc 00 00 00 00 00 ef 02 02 00 03 40 00 00 b9 00 00 c8 
00 00 01 00 00 07 00 00 07 00 00 00 00 00 02 00 00 00 00 00 d0 00 00 c8 
00 00 01 00 00 00 00 00 03 00 00 00 00 00 00 00 00 00 00 00 04 00 00 00 
00 00 04 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0e 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 12 ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 7a 4e 00 00 00 01 00 00 00 00 00 00 00 00 00 01 ff ff ff ff ff ff 
ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00

这看起来一点也不像字母“T”！

知道我做错了什么吗？谢谢！

有帮助吗？

解决方案

好的，我计算出来。我需要正确地设置的颜色，并使用之前绘制gdk_draw_rectangle清除该地区：

PangoLayout *layout = gtk_widget_create_pango_layout(me->gtk_window, "T");
int width, height;
PangoFontDescription *fontdesc = pango_font_description_from_string("Sans 10");
pango_layout_set_font_description (layout, fontdesc);
pango_layout_get_pixel_size (layout, &width, &height);

GdkPixmap *temp_pixmap = gdk_pixmap_new(NULL, width, height, 24);
GdkGC *gc = gdk_gc_new(temp_pixmap);

GdkColor white = {0,0xFF00,0xFF00,0xFF00};
GdkColor black = {0,0,0,0};

GdkColormap *cmap = gdk_gc_get_colormap(gc);

gdk_gc_set_rgb_fg_color(gc, &black);
gdk_gc_set_rgb_bg_color(gc, &white);
gdk_draw_rectangle(temp_pixmap, gc, TRUE, 0, 0, width, height);

gdk_gc_set_rgb_fg_color(gc, &white);
gdk_gc_set_rgb_bg_color(gc, &black);
gdk_draw_layout(temp_pixmap, gc, 0, 0, layout);

GdkPixbuf *temp_pixbuf = gdk_pixbuf_get_from_drawable(NULL, temp_pixmap,
                                        cmap, 0, 0, 0, 0, width, height);

int n_channels = gdk_pixbuf_get_n_channels (temp_pixbuf);
int rowstride = gdk_pixbuf_get_rowstride(temp_pixbuf);
guchar *pixels = gdk_pixbuf_get_pixels(temp_pixbuf);

int i,j;
for (j=0; j<height; j++) {
    for (i=0; i<(width*n_channels); i++) {
        printf("%02x ",
               *(pixels + i + j*rowstride));
    }
    printf("\n");
}

给我：

00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
c5 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff e3 
25 30 33 33 33 33 33 33 3d 68 ba f6 ff d8 86 4a 35 33 33 33 33 33 31 2a 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00

其他提示

只是一些基本提示，尚未尝试您的代码：

  • 你没有提到错误检查；您应该仔细检查并看到所有不同的 GTK+/GDK 调用都成功。它们都应该对输入进行 NULL 检查并发出警告，但仍然如此。
  • 您同时打印所有通道，这 可能 导致难以用视觉解释图像。我尝试过滤掉数据中的两个通道，但这没有帮助。当然，既然你说每次输出都不同，那这是一个不太可能的情况。
  • 我不确定 GDK 绘图调用的同步性，是否保证它们立即发生然后返回，或者是否可以推迟到稍后的“更新脏区域”处理程序。
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