如何输入从缓冲读者的字符串？

Question

林使用过多使用扫描仪主要和希望太尝试使用缓冲读取器： 继承人什么我迄今为止

import java.util.*;
import java.io.*;
public class IceCreamCone 
{
// variables
String flavour;
int numScoops;
Scanner flavourIceCream = new Scanner(System.in);

// constructor
public IceCreamCone()
{

}
// methods
public String getFlavour() throws IOexception 
{
    try{

    BufferedReader keyboardInput;
    keyboardInput = new BufferedReader(new InputStreamReader(System.in));
    System.out.println(" please enter your flavour ice cream");
    flavour  =  keyboardInput.readLine();
    return keyboardInput.readLine();
    }
    catch (IOexception e)
    {
        e.printStackTrace();
    }
}

即时通讯相当肯定获得一个int，你可以说

Integer.parseInt(keyboardInput.readLine());

但我做了什么，如果我想要一个字符串

Answer 1

keyboardInput.readLine()已经返回一个字符串，所以你应该简单地做：

return keyboardInput.readLine();

（更新）

在readLine方法抛出IOException。你要么抛出异常：

public String getFlavour() throws IOException {
   ...
}

或你处理它在你的方法。

public static String getFlavour() {
    BufferedReader keyboardInput = null;
    try {
        keyboardInput = new BufferedReader(new InputStreamReader(System.in));
        System.out.println(" please enter your flavour ice cream");
        // in this case, you don't need to declare this extra variable
        // String flavour = keyboardInput.readLine();
        // return flavour;
        return keyboardInput.readLine();
    } catch (IOException e) {
        // handle this
        e.printStackTrace();
    }
    return null;
}