模式匹配在PostgreSQL?[关闭]
-
26-09-2020 - |
题
我有一串其需要提取该日期,
例如:S01_XXX001_000_min_01_20150526T123440583.弧, S01_XXX001_000_20150526T123440583_min_01.弧
基于图像'数字T数字',
我正在尝试提取与下sql,任何一个可以帮助我。
SQL:
select substring('S01_ZAR001_000_min_01_20150526T123440583.arc','^\d')
select substring('SAPCC_XX_ZZZ_BitClass_XXX_20150623T45656566456_XXX_XX_XXXXXX.arc' like '_%T%_',1,8)
select substring('SAPCC_XX_ZZZ_BitClass_XXX_201506235T335656_XXX_XX_XXXXXX.arc','[^_]+([^0-9]{1,8})$')
SELECT SUBSTRING('XY1234Z', 'Y*([0-9]{1,3})');
解决方案
select substr(
substring('SAPCC_XX_ZZZ_Bit1T1Class_XXX_201506235T335656_XXX_XX_XXXXXX'
from
'_[0-9]+T[0-9]+_'
), 2, 8
)::date
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