在Visual C＃2008解析的tnsnames.ora

Question

如何我解析使用Visual C＃（Visual Studio 2008速成版），以获得TNSNAMES tnsnames.ora文件？ 例如，我的tnsnames.ora文件包含

ORCL =
  (DESCRIPTION =
    (ADDRESS = (PROTOCOL = TCP)(HOST = shaman)(PORT = 1521))
    (CONNECT_DATA =
      (SERVER = DEDICATED)
      (SERVICE_NAME = orcl)
    )
  )
BILL =
  (DESCRIPTION =
    (ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.10.58)(PORT = 1522))
    (CONNECT_DATA =
      (SERVER = DEDICATED)
      (SERVICE_NAME = orcl)
    )
  )

如何分析此文件，以获得TNSNAMES（即ORCL，BILL等）。原谅我，如果这个问题听起来太明显了，我在学习和尝试在C＃我的手

Answer 1

首先，你需要语法规则此文件。

有可能是这一个黑客，但我会亲自去一个完整的解析器，如 ANTLR 与适当语法（ANTLR语法的完整列表的可以在这里找到）。

Answer 2

public List<string> ReadTextFile(string FP)
{

    string inputString;
    List<string> List = new List<string>();

    try
    {
        StreamReader streamReader = File.OpenText(FP.Trim()); // FP is the filepath of TNS file

        inputString = streamReader.ReadToEnd();
        string[] temp = inputString.Split(new string[] {Environment.NewLine},StringSplitOptions.None);

        for (int i = 0; i < temp.Length ;i++ )
        {
            if (temp[i].Trim(' ', '(').Contains("DESCRIPTION"))
            {                   
                string DS = temp[i-1].Trim('=', ' ');
                List.Add(DS);
            }             

        }
        streamReader.Close();
    }
    catch (Exception EX)
    {
    }


    return List;

}

Answer 3

与由沙迪亚提供的那些一起，创建一个方法：

StringBuilder strTns = new StringBuilder ();

foreach ( var fileLine in System.IO.File.ReadAllLines(fiTNS.FullName ) )
{
    if ( (fileLine.Length > 0 
           && fileLine.Trim().Substring(0,1) != "#" 
          )
          && ( fileLine.Length > 0 
                && fileLine.Trim ().Substring (0,1) != "/" 
              )
        )

        {
           strTns.AppendFormat("{0}{1}", fileLine, Environment.NewLine);
        }
}

//TNSNamesValues = System.IO.File.ReadAllText (fiTNS.FullName).ToString ().Replace ("\n", "" ).Replace ("\r", "");
String[] splitSeparator = LoadTNSNames (OracleHomeRegistryKey).ToArray ();
String[] TNS = strTns.ToString().Split (splitSeparator, StringSplitOptions.None);