在KSH PUSHD / POPD？
https://stackoverflow.com/questions/984635
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是否有命令为KSH在bash PUSHD / POPD构建的等效？
对于那些谁不知道什么pushd和popd命令在bash做，这里是从该名男子页的说明
pushd [-n] [dir]
pushd [-n] [+n] [-n]
Adds a directory to the top of the directory stack, or rotates
the stack, making the new top of the stack the current working
directory. With no arguments, exchanges the top two directo-
ries and returns 0, unless the directory stack is empty.
popd [-n] [+n] [-n]
Removes entries from the directory stack. With no arguments,
removes the top directory from the stack, and performs a cd to
the new top directory. Arguments, if supplied, have the fol-
lowing meanings:
由于
解决方案
当我发现KSH不包括这些，我写我自己。我把这个~/bin/dirstack.ksh和我.kshrc文件包括这样的：
. ~/bin/dirstack.ksh
下面是dirstack.ksh的内容：
# Implement a csh-like directory stack in ksh
#
# environment variable dir_stack contains all directory entries except
# the current directory
unset dir_stack
export dir_stack
# Three forms of the pushd command:
# pushd - swap the top two stack entries
# pushd +3 - swap top stack entry and entry 3 from top
# pushd newdir - cd to newdir, creating new stack entry
function pushd
{
sd=${#dir_stack[*]} # get total stack depth
if [ $1 ] ; then
if [ ${1#\+[0-9]*} ] ; then
# ======= "pushd dir" =======
# is "dir" reachable?
if [ `(cd $1) 2>/dev/null; echo $?` -ne 0 ] ; then
cd $1 # get the actual shell error message
return 1 # return complaint status
fi
# yes, we can reach the new directory; continue
(( sd = sd + 1 )) # stack gets one deeper
dir_stack[sd]=$PWD
cd $1
# check for duplicate stack entries
# current "top of stack" = ids; compare ids+dsdel to $PWD
# either "ids" or "dsdel" must increment with each loop
#
(( ids = 1 )) # loop from bottom of stack up
(( dsdel = 0 )) # no deleted entries yet
while [ ids+dsdel -le sd ] ; do
if [ "${dir_stack[ids+dsdel]}" = "$PWD" ] ; then
(( dsdel = dsdel + 1 )) # logically remove duplicate
else
if [ dsdel -gt 0 ] ; then # copy down
dir_stack[ids]="${dir_stack[ids+dsdel]}"
fi
(( ids = ids + 1 ))
fi
done
# delete any junk left at stack top (after deleting dups)
while [ ids -le sd ] ; do
unset dir_stack[ids]
(( ids = ids + 1 ))
done
unset ids
unset dsdel
else
# ======= "pushd +n" =======
(( sd = sd + 1 - ${1#\+} )) # Go 'n - 1' down from the stack top
if [ sd -lt 1 ] ; then (( sd = 1 )) ; fi
cd ${dir_stack[sd]} # Swap stack top with +n position
dir_stack[sd]=$OLDPWD
fi
else
# ======= "pushd" =======
cd ${dir_stack[sd]} # Swap stack top with +1 position
dir_stack[sd]=$OLDPWD
fi
}
function popd
{
sd=${#dir_stack[*]}
if [ $sd -gt 0 ] ; then
cd ${dir_stack[sd]}
unset dir_stack[sd]
else
cd ~
fi
}
function dirs
{
echo "0: $PWD"
sd=${#dir_stack[*]}
(( ind = 1 ))
while [ $sd -gt 0 ]
do
echo "$ind: ${dir_stack[sd]}"
(( sd = sd - 1 ))
(( ind = ind + 1 ))
done
}
其他提示
如果你都OK背部的只是一个单一的追踪，您可以别名“CD - ”或“CD $ OLDPWD”到POPD
至于dir.ksh ......根据谷歌这是一个
请注意
POPD定义一个KornShell函数 在文件
$ROOTDIR/etc/dir.ksh.此文件通常由处理 的处理过程中登录壳 文件$ ROOTDIR的/ etc / profile.ksh。如果 你的系统无法识别 POPD命令，检查你的profile.ksh 文件，以确保调用dir.ksh 被包括。
AVAILABILITY
MKS工具箱高级用户MKS 工具包为系统管理员MKS 工具包开发MKS工具包 互操作性MKS工具包 专业开发者工具包MKS 为企业开发人员工具包MKS 企业开发者64位 版
我通常使用子外壳为这样的事情：
(cd tmp; echo "test" >tmpfile)
此改变到目录tmp和创建一个名为tmpfile在该目录中的文件。子shell返回后，当前目录恢复到什么是子shell启动之前。这是因为每个shell实例都有自己什么样的“当前目录”的理念，并在子shell改变当前目录不会影响调用它的外壳。
有一个在接受的答案个微妙的问题。当“PUSHD”是没有ARG（$ 1 =“”）调用和空dir_stack，它注入空进入，不能说栈“弹出”出来的。捕捉边缘的情况下，似乎解决它。
这里的校正码。编辑：抱怨到stderr时无处可推一致（W / bash的PUSHD）。留在“显示目录”，因为我觉得这是一个改进的索引列表：'）
# Implement a csh-like directory stack in ksh
#
# environment variable dir_stack contains all directory entries except
# the current directory
unset dir_stack
export dir_stack
# Three forms of the pushd command:
# pushd - swap the top two stack entries
# pushd +3 - swap top stack entry and entry 3 from top
# pushd newdir - cd to newdir, creating new stack entry
function pushd
{
sd=${#dir_stack[*]} # get total stack depth
if [ $1 ] ; then
if [ ${1#\+[0-9]*} ] ; then
# ======= "pushd dir" =======
# is "dir" reachable?
if [ `(cd $1) 2>/dev/null; echo $?` -ne 0 ] ; then
cd $1 # get the actual shell error message
return 1 # return complaint status
fi
# yes, we can reach the new directory; continue
(( sd = sd + 1 )) # stack gets one deeper
dir_stack[sd]=$PWD
cd $1
# check for duplicate stack entries
# current "top of stack" = ids; compare ids+dsdel to $PWD
# either "ids" or "dsdel" must increment with each loop
#
(( ids = 1 )) # loop from bottom of stack up
(( dsdel = 0 )) # no deleted entries yet
while [ ids+dsdel -le sd ] ; do
if [ "${dir_stack[ids+dsdel]}" = "$PWD" ] ; then
(( dsdel = dsdel + 1 )) # logically remove duplicate
else
if [ dsdel -gt 0 ] ; then # copy down
dir_stack[ids]="${dir_stack[ids+dsdel]}"
fi
(( ids = ids + 1 ))
fi
done
# delete any junk left at stack top (after deleting dups)
while [ ids -le sd ] ; do
unset dir_stack[ids]
(( ids = ids + 1 ))
done
unset ids
unset dsdel
else
# ======= "pushd +n" =======
(( sd = sd + 1 - ${1#\+} )) # Go 'n - 1' down from the stack top
if [ sd -lt 1 ] ; then (( sd = 1 )) ; fi
cd ${dir_stack[sd]} # Swap stack top with +n position
dir_stack[sd]=$OLDPWD
fi
else
# ======= "pushd" =======
# swap only if there's a value to swap with
if [ ${#dir_stack[*]} = "0" ]; then
echo "ksh: pushd: no other directory" >&2
else
cd ${dir_stack[sd]} # Swap stack top with +1 position
dir_stack[sd]=$OLDPWD
fi
fi
}
function popd
{
sd=${#dir_stack[*]}
if [ $sd -gt 0 ] ; then
cd ${dir_stack[sd]}
unset dir_stack[sd]
else
cd ~
fi
}
function dirs
{
echo "0: $PWD"
sd=${#dir_stack[*]}
(( ind = 1 ))
while [ $sd -gt 0 ]
do
echo "$ind: ${dir_stack[sd]}"
(( sd = sd - 1 ))
(( ind = ind + 1 ))
done
}
如果您的系统无法识别pushd命令，请检查您profile.ksh文件，以确保包括到dir.ksh通话。
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