题
我有一个清单 Foo
. 。Foo 有属性 Bar
和 Lum
. 。一些 Foo
s 具有相同的值 Bar
. 。我如何使用 lambda/linq 对我的 Foo
是由 Bar
这样我就可以迭代每个分组的 Lum
是?
解决方案
迪诺,
享受:
var foos = new List<Foo> {
new Foo{Bar = 1,Lum = 1},
new Foo{Bar = 1,Lum = 2},
new Foo{Bar = 2,Lum = 3},
};
// Using language integrated queries:
var q = from foo in foos
group foo by foo.Bar into groupedFoos
let lums = from fooGroup in groupedFoos
select fooGroup.Lum
select new { Bar = groupedFoos.Key, Lums = lums };
// Using lambdas
var q = foos.GroupBy(x => x.Bar).
Select(y => new {Bar = y.Key, Lums = y.Select(z => z.Lum)});
foreach (var group in q)
{
Console.WriteLine("Lums for Bar#" + group.Bar);
foreach (var lum in group.Lums)
{
Console.WriteLine(lum);
}
}
要了解有关 LINQ 的更多信息,请阅读 101 个 LINQ 示例
其他提示
var q = from x in list
group x by x.Bar into g
select g;
foreach (var group in q)
{
Console.WriteLine("Group " + group.Key);
foreach (var item in group)
{
Console.WriteLine(item.Bar);
}
}
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