题
假设有两个表。
Table X--
Columns:
id x_value
Table Y--
Columns:
id x_id y_value
现在我不想定义教义班的关系,我想检索使用使用这样的查询这两个表的一些记录:
Select x_value from x, y where y.id="variable_z" and x.id=y.x_id;
我不是能够想出如何在教义ORM写查询这样
修改强>
表结构:
表1:
CREATE TABLE IF NOT EXISTS `image` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`random_name` varchar(255) NOT NULL,
`user_id` int(11) NOT NULL,
`community_id` int(11) NOT NULL,
`published` varchar(1) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ;
表2:
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`city` varchar(20) DEFAULT NULL,
`state` varchar(20) DEFAULT NULL,
`school` varchar(50) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;
我使用查询:
$q = new Doctrine_RawSql();
$q ->select('{u.*}, {img.*}')
->from('users u LEFT JOIN image img ON u.id = img.user_id')
->addComponent('u', 'Users u')
->addComponent('img', 'u.Image img')
->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city
->orderBy('img.id DESC')
->limit($count+12)
->execute();
错误我得到:
Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class
u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php:290 Stack trace: #0
C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php(240): Doctrine_Table- >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.php(1127):
Doctrine_Table->__construct('u', Object(Doctrine_Connection_Mysql), true) #2
C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\RawSql.php(425): Doctrine_Connection-
>getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.php(33): Doctrine_RawSql-
>addComponent('img', 'u.Image imga') #4 C:\xampp\htdocs\fanyer\community_images.php(31):
Image->get_community_images_gallery_filter(4, 0, 'AL', 'ALBERTVILLE') #5 {main} thrown in
C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php on line 290
解决方案
尝试是这样的:---
$q = new Doctrine_RawSql();
$this->related_objects = $q->
select('{o.name}')->
from('tagset t1 JOIN tagset t2 ON t1.tag_id = t2.tag_id AND t1.object_id != t2.object_id JOIN object o ON t2.object_id = o.id')->
addComponent('o','Object o')->
where('t1.object_id = ?', $this->object->id)->
groupBy('t2.object_id')->
orderBy('COUNT(*) DESC')->
execute();
其他提示
您可以直接编写SQL的数据库driver.You不会得到任何回水合数组或对象。然而。但它确实派上用场,有时
$sql = "SELECT * FROM... ";
$pdo = Doctrine_Manager::connection()->getDbh();
$data = $pdo->query($sql)->fetchAll();
您可以手动改变你的表格类中的Symfony 1.4但这应该小心操作,因为你不是在连接数据库级表通常应该发生。
class TableName extends BaseTableName
{
public function setUp()
{
$this->hasOne('LinkedTableName', array(
'local' => 'link_id',
'foreign' => 'link_id'));
parent::setUp();
}
}
可能重复:教义加入
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