假设有两个表。

Table X--
Columns:
     id         x_value

Table Y--
Columns:
     id        x_id      y_value

现在我不想定义教义班的关系,我想检索使用使用这样的查询这两个表的一些记录:

Select x_value from x, y where y.id="variable_z" and x.id=y.x_id;

我不是能够想出如何在教义ORM写查询这样

修改

表结构:

表1:

CREATE TABLE IF NOT EXISTS `image` (
  `id` int(11) NOT NULL AUTO_INCREMENT, 
`random_name` varchar(255) NOT NULL,
 `user_id` int(11) NOT NULL,
  `community_id` int(11) NOT NULL,
  `published` varchar(1) NOT NULL,
  PRIMARY KEY (`id`)
 ) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ;

表2:

  CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
   `city` varchar(20) DEFAULT NULL,
   `state` varchar(20) DEFAULT NULL,
   `school` varchar(50) DEFAULT NULL,
   PRIMARY KEY (`id`)
 ) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;

我使用查询:

        $q = new Doctrine_RawSql();

        $q  ->select('{u.*}, {img.*}')
        ->from('users u LEFT JOIN image img ON u.id = img.user_id')
        ->addComponent('u', 'Users u')
        ->addComponent('img', 'u.Image img')
        ->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city
        ->orderBy('img.id DESC')
        ->limit($count+12)  
        ->execute();        

错误我得到:

 Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class
 u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php:290 Stack trace: #0 
 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php(240): Doctrine_Table-   >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.php(1127): 
Doctrine_Table->__construct('u', Object(Doctrine_Connection_Mysql), true) #2 
C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\RawSql.php(425): Doctrine_Connection-
>getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.php(33):    Doctrine_RawSql-
>addComponent('img', 'u.Image imga') #4   C:\xampp\htdocs\fanyer\community_images.php(31): 
  Image->get_community_images_gallery_filter(4, 0, 'AL', 'ALBERTVILLE') #5 {main} thrown      in 
    C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php  on line 290
有帮助吗?

解决方案

尝试是这样的:---

$q = new Doctrine_RawSql();
$this->related_objects = $q->
        select('{o.name}')->
        from('tagset t1 JOIN tagset t2 ON t1.tag_id = t2.tag_id AND t1.object_id != t2.object_id JOIN object o ON t2.object_id = o.id')->
        addComponent('o','Object o')->
        where('t1.object_id = ?', $this->object->id)->
        groupBy('t2.object_id')->
        orderBy('COUNT(*) DESC')->
        execute();

其他提示

您可以直接编写SQL的数据库driver.You不会得到任何回水合数组或对象。然而。但它确实派上用场,有时

 $sql = "SELECT * FROM... ";        
 $pdo = Doctrine_Manager::connection()->getDbh();       
 $data = $pdo->query($sql)->fetchAll();

您可以手动改变你的表格类中的Symfony 1.4但这应该小心操作,因为你不是在连接数据库级表通常应该发生。

class TableName extends BaseTableName
{
    public function setUp()
    {
        $this->hasOne('LinkedTableName', array(
             'local' => 'link_id',
             'foreign' => 'link_id'));
        parent::setUp();
    }
}

可能重复:教义加入

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