如何在 Windows 上的 Python 中等待多个子进程,而不需要主动等待(轮询)?像这样的东西 几乎 对我有用:

proc1 = subprocess.Popen(['python','mytest.py'])
proc2 = subprocess.Popen(['python','mytest.py'])    
proc1.wait()
print "1 finished"
proc2.wait()
print "2 finished"

问题是当 proc2 之前完成 proc1, ,父进程仍然会等待 proc1. 。在 Unix 上会使用 waitpid(0) 在循环中获取子进程完成时的返回码 - 如何在 Windows 上的 Python 中实现类似的功能?

有帮助吗?

解决方案

这可能看起来有点矫枉过正,但是,事情是这样的:

import Queue, thread, subprocess

results= Queue.Queue()
def process_waiter(popen, description, que):
    try: popen.wait()
    finally: que.put( (description, popen.returncode) )
process_count= 0

proc1= subprocess.Popen( ['python', 'mytest.py'] )
thread.start_new_thread(process_waiter,
    (proc1, "1 finished", results))
process_count+= 1

proc2= subprocess.Popen( ['python', 'mytest.py'] )
thread.start_new_thread(process_waiter,
    (proc2, "2 finished", results))
process_count+= 1

# etc

while process_count > 0:
    description, rc= results.get()
    print "job", description, "ended with rc =", rc
    process_count-= 1

其他提示

扭曲有一个 异步进程生成 API 它适用于Windows。实际上有几种不同的实现,其中许多都不是很好,但是您可以在不更改代码的情况下在它们之间进行切换。

基于 zseil 的答案,您可以通过混合使用子进程和 win32 API 调用来实现此目的。我直接使用 ctypes,因为我的 Python 碰巧没有安装 win32api。我只是在这里从 MSYS 生成 sleep.exe 作为示例,但显然您可以生成您喜欢的任何进程。我使用 OpenProcess() 从进程的 PID 获取句柄,然后使用 WaitForMultipleObjects 等待任何进程完成。

import ctypes, subprocess
from random import randint
SYNCHRONIZE=0x00100000
INFINITE = -1
numprocs = 5
handles = {}

for i in xrange(numprocs):
    sleeptime = randint(5,10)
    p = subprocess.Popen([r"c:\msys\1.0\bin\sleep.exe", str(sleeptime)], stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=False)
    h = ctypes.windll.kernel32.OpenProcess(SYNCHRONIZE, False, p.pid)
    handles[h] = p.pid
    print "Spawned Process %d" % p.pid

while len(handles) > 0:
    print "Waiting for %d children..." % len(handles)
    arrtype = ctypes.c_long * len(handles)
    handle_array = arrtype(*handles.keys())
    ret = ctypes.windll.kernel32.WaitForMultipleObjects(len(handle_array), handle_array, False, INFINITE)
    h = handle_array[ret]
    ctypes.windll.kernel32.CloseHandle(h)
    print "Process %d done" % handles[h]
    del handles[h]
print "All done!"

Windows 上的 Twisted 将在幕后执行主动等待。如果您不想使用线程,则必须使用 win32 API 来避免轮询。像这样的东西:

import win32process
import win32event

# Note: CreateProcess() args are somewhat cryptic, look them up on MSDN
proc1, thread1, pid1, tid1 = win32process.CreateProcess(...)
proc2, thread2, pid2, tid2 = win32process.CreateProcess(...)
thread1.close()
thread2.close()

processes = {proc1: "proc1", proc2: "proc2"}

while processes:
    handles = processes.keys()
    # Note: WaitForMultipleObjects() supports at most 64 processes at a time
    index = win32event.WaitForMultipleObjects(handles, False, win32event.INFINITE)
    finished = handles[index]
    exitcode = win32process.GetExitCodeProcess(finished)
    procname = processes.pop(finished)
    finished.close()
    print "Subprocess %s finished with exit code %d" % (procname, exitcode)

您可以使用 普苏蒂尔:

>>> import subprocess
>>> import psutil
>>> 
>>> proc1 = subprocess.Popen(['python','mytest.py'])
>>> proc2 = subprocess.Popen(['python','mytest.py'])    
>>> ls = [psutil.Process(proc1.pid), psutil.Process(proc2.pid)]
>>>
>>> gone, alive = psutil.wait_procs(ls, timeout=3)

“gone”和“alive”是指示哪些进程已消失以及哪些进程仍处于活动状态的列表。

您可以选择指定一个回调,每次监视的进程之一终止时都会调用该回调:

>>> def on_terminate(proc):
...     print "%s terminated" % proc
...
>>> gone, alive = psutil.wait_procs(ls, timeout=3, callback=on_terminate)
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