I am trying to understand the following code:

#include<stdio.h>
#include<stdlib.h>
#include<sys/io.h>

#define baseport 0x378

int main()
{
    int b;
    if(ioperm(baseport,3,1))
    {
        perror("ioperm");
        exit(1);
    }
    outb(0,baseport);

    usleep(1000000);
    printf("\n the status: %x,\n",inb(baseport));

    if (ioperm(baseport,3,0)) {perror("ioperm"); exit(1);}

    exit(0);
}

The output is 0xff, 255 in decimal, whether I write on Port 1 or Port 0 (using outb()). I cannot understand why it is 255 when I am writing 0 to it.

有帮助吗?

解决方案

The result of doing inb(0x378) is hardware-dependent. Some chips return the value you have written previously with outb, and some other chips just return garbage. In any case, it is not the port to read bytes from a potentially connected device.

其他提示

first see, how the port can behave, as input or output or both!!!.. if it can be configured as both .. you have to set to respective mode then only you can expect the right behaviour ..

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