题
是否LINQ模型聚集SQL函数STDDEV()
(标准偏差)?
如果没有,什么是最简单的/最佳实践的方法来计算呢?
示例:
SELECT test_id, AVERAGE(result) avg, STDDEV(result) std
FROM tests
GROUP BY test_id
解决方案
您可以让自己的分机计算它
public static class Extensions
{
public static double StdDev(this IEnumerable<double> values)
{
double ret = 0;
int count = values.Count();
if (count > 1)
{
//Compute the Average
double avg = values.Average();
//Perform the Sum of (value-avg)^2
double sum = values.Sum(d => (d - avg) * (d - avg));
//Put it all together
ret = Math.Sqrt(sum / count);
}
return ret;
}
}
如果你有一个的样品的人口,而不是总人口的,那么你应该使用ret = Math.Sqrt(sum / (count - 1));
。
转化成延伸部从添加标准偏差LINQ由Chris贝内特。
其他提示
Dynami的答复工作,但使得通过数据多遍以得到一个结果。这是计算的样本标准偏差单程方式:
public static double StdDev(this IEnumerable<double> values)
{
// ref: http://warrenseen.com/blog/2006/03/13/how-to-calculate-standard-deviation/
double mean = 0.0;
double sum = 0.0;
double stdDev = 0.0;
int n = 0;
foreach (double val in values)
{
n++;
double delta = val - mean;
mean += delta / n;
sum += delta * (val - mean);
}
if (1 < n)
stdDev = Math.Sqrt(sum / (n - 1));
return stdDev;
}
这是样本标准偏差因为它除以n - 1
。对于普通的标准偏差则需要通过n
代替来划分。
此戴维·克拉克的回答转换成遵循相同的形式等平均的其他聚合LINQ功能的扩展。
用法是:var stdev = data.StdDev(o => o.number)
public static class Extensions
{
public static double StdDev<T>(this IEnumerable<T> list, Func<T, double> values)
{
// ref: https://stackoverflow.com/questions/2253874/linq-equivalent-for-standard-deviation
// ref: http://warrenseen.com/blog/2006/03/13/how-to-calculate-standard-deviation/
var mean = 0.0;
var sum = 0.0;
var stdDev = 0.0;
var n = 0;
foreach (var value in list.Select(values))
{
n++;
var delta = value - mean;
mean += delta / n;
sum += delta * (value - mean);
}
if (1 < n)
stdDev = Math.Sqrt(sum / (n - 1));
return stdDev;
}
}
var stddev = Math.Sqrt(data.Average(z=>z*z)-Math.Pow(data.Average(),2));
直于点(和C#> 6.0),DYNAMIS答案变成这样:
public static double StdDev(this IEnumerable<double> values)
{
var count = values?.Count() ?? 0;
if (count <= 1) return 0;
var avg = values.Average();
var sum = values.Sum(d => Math.Pow(d - avg, 2));
return Math.Sqrt(sum / count);
}
public static double StdDev(this IEnumerable<int> values, bool as_sample = false)
{
var count = values.Count();
if (count > 0) // check for divide by zero
// Get the mean.
double mean = values.Sum() / count;
// Get the sum of the squares of the differences
// between the values and the mean.
var squares_query =
from int value in values
select (value - mean) * (value - mean);
double sum_of_squares = squares_query.Sum();
return Math.Sqrt(sum_of_squares / (count - (as_sample ? 1 : 0)))
}
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