Converting integer to datetime in Python [closed]

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Closed 8 years ago.

My code:

import datetime as dt
import scikits.timeseries as ts

ts_start_datetime= ts.Date(freq='T',year=2011,month=1,day=1,hour= 0,minute=0)
ts_end_datetime = ts.Date(freq='T',year=2011,month=12,day=31,hour=23,minute=45)

start_val = ts_start_datetime.value
#   21564001
end_val = ts_end_datetime.value
#   22089586

How do I convert start_val and end_val to datetime objects?

Answer 1

Use datetime.fromtimestamp(), since your values appear to be minutes rather than seconds, first multiply them by 60:

start_dt = dt.datetime.fromtimestamp(start_val * 60)
end_dt = dt.datetime.fromtimestamp(end_val * 60)

If you want a UTC time instead of a local time, use datetime.utcfromtimestamp():

>>> dt.datetime.utcfromtimestamp(21564001 * 60)
datetime.datetime(2011, 1, 1, 0, 1)
>>> dt.datetime.utcfromtimestamp(22089586 * 60)
datetime.datetime(2011, 12, 31, 23, 46)

I'm not exactly sure why each of these are one minute after what you started with, you can always subtract 60 before the call or subtract dt.timedelta(minutes=1) from the end result.