我需要下载文本文件的zip存档,将存档中的每个文本文件派遣到其他处理程序进行处理,最后将未拉链的文本文件写入磁盘。

我有以下代码。它在同一文件上使用多个打开/关闭,这似乎并不优雅。如何使其更优雅和高效?

zipped = urllib.urlopen('www.abc.com/xyz.zip')
buf = cStringIO.StringIO(zipped.read())
zipped.close()
unzipped = zipfile.ZipFile(buf, 'r')
for f_info in unzipped.infolist():
   logfile = unzipped.open(f_info)
   handler1(logfile)
   logfile.close()   ## Cannot seek(0). The file like obj does not support seek()
   logfile = unzipped.open(f_info)
   handler2(logfile)
   logfile.close()
   unzipped.extract(f_info)
有帮助吗?

解决方案

您的答案在您的示例代码中。只需使用Stringio来缓冲日志文件:

zipped = urllib.urlopen('www.abc.com/xyz.zip')
buf = cStringIO.StringIO(zipped.read())
zipped.close()
unzipped = zipfile.ZipFile(buf, 'r')
for f_info in unzipped.infolist():
   logfile = unzipped.open(f_info)
   # Here's where we buffer:
   logbuffer = cStringIO.StringIO(logfile.read())
   logfile.close()

   for handler in [handler1, handler2]:
      handler(logbuffer)
      # StringIO objects support seek():
      logbuffer.seek(0)

   unzipped.extract(f_info)

其他提示

您可以说类似:

handler_dispatch(logfile)

def handler_dispatch(file):
   for line in file:
      handler1(line)
      handler2(line)

甚至通过构建具有多个处理程序的处理程序类,并将它们都应用到其中,甚至使其更具动态性 handler_dispatch. 。喜欢

class Handler:
    def __init__(self:)
        self.handlers = []

  def add_handler(handler):
      self.handlers.append(handler)

  def handler_dispatch(self, file):
      for line in file:
          for handler in self.handlers:
              handler.handle(line)

打开一次zip文件,循环浏览所有名称,提取每个名称的文件并处理它,然后将其写入磁盘。

像这样:

for f_info in unzipped.info_list():
    file = unzipped.open(f_info)
    data = file.read()
    # If you need a file like object, wrap it in a cStringIO
    fobj = cStringIO.StringIO(data)
    handler1(fobj)
    handler2(fobj)
    with open(filename,"w") as fp:
        fp.write(data)

你明白了

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