如何获得秒，因为在VBA时代（1/1/1970）？

Question

我怎样才能得到秒，因为在 VBA 时期（1/1/1970）<？ / p>

Answer 1

如何：

datediff("s",#1970/1/1#,now())

Answer 2

这应该运行比DateDiff的解决方案快：

Private Function Long2Date(lngDate As Long) As Date
    Long2Date = lngDate / 86400# + #1/1/1970#
End Function

Private Function Date2Long(dtmDate As Date) As Long
    Date2Long = (dtmDate - #1/1/1970#) * 86400
End Function

Answer 3

这里的一个解决方案： http://vbcity.com/forums/t/5084.aspx

Function UnixTime() As Variant
    'The first parameter determines how the 
    ' difference will be measured in i.e. "S" for seconds
    UnixTime = DateDiff("S", "1/1/1970", Now())
End Function

Answer 4

我tryed修改它为我的时区和 考虑到DST。时区可以具有diferent设置当它改变。

Function Epoch2Date(lngDate As Long) As Date
'transfer to date
    Epoch2Date = lngDate / 86400# + #1/1/1970#
'check if it is summer time
    If IsDST(Epoch2Date) = False Then
'here you can use diferent values depend on time zone
    Epoch2Date = Epoch2Date - 0.041666667
    Else
    Epoch2Date = Epoch2Date - 0.0833333333333333
    End If
End Function

Public Function IsDST(ByVal d0 As Date) As Boolean
   IsDST = d0 >= NextSun("24.3." & Year(d0) & " 01:59:59") And d0 < NextSun("24.10." & Year(d0) & " 01:59:59")
End Function

Private Function NextSun(d1 As Date) As Date
        'if 24.3 or 24.10 is sunday returns 31.3 or 31.10
        If Weekday(d1, vbMonday) = 7 Then
            NextSun = d1 + 7
        Else
        'if not return nearest sunday
            NextSun = d1 + 7 - Weekday(d1, vbMonday)
        End If
    End Function

Answer 5

DateDiff("s", "01/01/1970 00:00:00", Now())＆Format(Now(), "ms")