题
我有在它的数字(5,9,3)的列表。让我们把它MYLIST
我想执行
var results = from a in myEntities.thing1 where a.ID belongsto MyList select a;
现在我
List<T> t = new List<T>(); //I actually define T to a strong type
foreach (int i in MyList)
{
t.add(from a in myEntities.thing1 where a.ID==i select a);
}
我敢肯定,必须有一个更好的办法,但我不能完全换我的头周围。
解决方案
var results = from a in myEntities.thing1 where MyList.Contains(a) select a;
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