HTML。ActionLink方法
-
03-07-2019 - |
题
让我们说有一个类
public class ItemController:Controller
{
public ActionResult Login(int id)
{
return View("Hi", id);
}
}
在一个页面上是不是位于该项目的文件夹,里 ItemController
驻留,我希望创建一个链接到 Login
法。所以这 Html.ActionLink
方法,我应该使用哪些参数应当我通过吗?
具体地说,我正在寻找替代的方法
Html.ActionLink(article.Title,
new { controller = "Articles", action = "Details",
id = article.ArticleID })
已退休的在最近ASP.NET 视的化身。
解决方案
我觉得你想要的是这个:
ASP.NET MVC1
Html.ActionLink(article.Title,
"Login", // <-- Controller Name.
"Item", // <-- ActionMethod
new { id = article.ArticleID }, // <-- Route arguments.
null // <-- htmlArguments .. which are none. You need this value
// otherwise you call the WRONG method ...
// (refer to comments, below).
)
这将使用以下方法ActionLink签署:
public static string ActionLink(this HtmlHelper htmlHelper,
string linkText,
string controllerName,
string actionName,
object values,
object htmlAttributes)
ASP.NET MVC2
两个论点已经被切换周围
Html.ActionLink(article.Title,
"Item", // <-- ActionMethod
"Login", // <-- Controller Name.
new { id = article.ArticleID }, // <-- Route arguments.
null // <-- htmlArguments .. which are none. You need this value
// otherwise you call the WRONG method ...
// (refer to comments, below).
)
这将使用以下方法ActionLink签署:
public static string ActionLink(this HtmlHelper htmlHelper,
string linkText,
string actionName,
string controllerName,
object values,
object htmlAttributes)
ASP.NET MVC3+
论据是相同的顺序MVC2,但是id价值不再是必需的:
Html.ActionLink(article.Title,
"Item", // <-- ActionMethod
"Login", // <-- Controller Name.
new { article.ArticleID }, // <-- Route arguments.
null // <-- htmlArguments .. which are none. You need this value
// otherwise you call the WRONG method ...
// (refer to comments, below).
)
这样可以避免硬编码的任何路逻辑的链接。
<a href="/Item/Login/5">Title</a>
这会给你下面html输出,假设:
article.Title = "Title"
article.ArticleID = 5
- 你还有下列路线的定义
. .
routes.MapRoute(
"Default", // Route name
"{controller}/{action}/{id}", // URL with parameters
new { controller = "Home", action = "Index", id = "" } // Parameter defaults
);
其他提示
我想添加到 Joseph Kingry的回答。他提供了解决方案,但起初我无法让它工作,并得到像Adhip Gupta一样的结果。然后我意识到路线必须首先存在,参数需要与路线完全匹配。所以我有一个id,然后是我的路线的文本参数,也需要包括在内。
Html.ActionLink(article.Title, "Login", "Item", new { id = article.ArticleID, title = article.Title }, null)
您可能需要查看 RouteLink()
method.That允许您通过字典指定所有内容(链接文本和路由名称除外)。
我认为约瑟夫翻转了控制器和动作。首先是动作然后是控制器。这有点奇怪,但签名的样子。
为了澄清事情,这是有效的版本(改编约瑟夫的例子):
Html.ActionLink(article.Title,
"Login", // <-- ActionMethod
"Item", // <-- Controller Name
new { id = article.ArticleID }, // <-- Route arguments.
null // <-- htmlArguments .. which are none
)
这个怎么样
<%=Html.ActionLink("Get Involved",
"Show",
"Home",
new
{
id = "GetInvolved"
},
new {
@class = "menuitem",
id = "menu_getinvolved"
}
)%>
Html.ActionLink(article.Title, "Login/" + article.ArticleID, 'Item")
如果你想穿上所有的花式裤子,可以通过以下方式扩展它以便能够做到这一点:
@(Html.ActionLink<ArticlesController>(x => x.Details(), article.Title, new { id = article.ArticleID }))
您需要将其放在System.Web.Mvc
命名空间中:
public static class MyProjectExtensions
{
public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText)
{
var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);
var link = new TagBuilder("a");
string actionName = ExpressionHelper.GetExpressionText(expression);
string controllerName = typeof(TController).Name.Replace("Controller", "");
link.MergeAttribute("href", urlHelper.Action(actionName, controllerName));
link.SetInnerText(linkText);
return new MvcHtmlString(link.ToString());
}
public static MvcHtmlString ActionLink<TController, TAction>(this HtmlHelper htmlHelper, Expression<Action<TController, TAction>> expression, string linkText, object routeValues)
{
var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);
var link = new TagBuilder("a");
string actionName = ExpressionHelper.GetExpressionText(expression);
string controllerName = typeof(TController).Name.Replace("Controller", "");
link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
link.SetInnerText(linkText);
return new MvcHtmlString(link.ToString());
}
public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText, object routeValues, object htmlAttributes) where TController : Controller
{
var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);
var attributes = AnonymousObjectToKeyValue(htmlAttributes);
var link = new TagBuilder("a");
string actionName = ExpressionHelper.GetExpressionText(expression);
string controllerName = typeof(TController).Name.Replace("Controller", "");
link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
link.MergeAttributes(attributes, true);
link.SetInnerText(linkText);
return new MvcHtmlString(link.ToString());
}
private static Dictionary<string, object> AnonymousObjectToKeyValue(object anonymousObject)
{
var dictionary = new Dictionary<string, object>();
if (anonymousObject == null) return dictionary;
foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(anonymousObject))
{
dictionary.Add(propertyDescriptor.Name, propertyDescriptor.GetValue(anonymousObject));
}
return dictionary;
}
}
这包括Route Values
和HTML Attributes
的两个覆盖,以及您需要添加的所有视图:@using YourProject.Controllers
或者您可以将其添加到web.config <pages><namespaces>
使用命名参数以提高可读性并避免混淆。
@Html.ActionLink(
linkText: "Click Here",
actionName: "Action",
controllerName: "Home",
routeValues: new { Identity = 2577 },
htmlAttributes: null)
使用MVC5,我已经这样做了,它是100%正常工作的代码......
@Html.ActionLink(department.Name, "Index", "Employee", new {
departmentId = department.DepartmentID }, null)
你们可以从中得到一个想法...
此类型使用:
@ Html.ActionLink(QUOT <!>;的MainPage QUOT <!>; <!>和quot;索引QUOT <!>; <!>和quot;首页QUOT <!>)
MainPage:文本名称 索引:动作视图 主页:HomeController
Base Use ActionLink
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>_Layout</title>
<link href="@Url.Content("~/Content/bootsrap.min.css")" rel="stylesheet" type="text/css" />
</head>
<body>
<div class="container">
<div class="col-md-12">
<button class="btn btn-default" type="submit">@Html.ActionLink("AnaSayfa","Index","Home")</button>
<button class="btn btn-default" type="submit">@Html.ActionLink("Hakkımızda", "Hakkimizda", "Home")</button>
<button class="btn btn-default" type="submit">@Html.ActionLink("Iletişim", "Iletisim", "Home")</button>
</div>
@RenderBody()
<div class="col-md-12" style="height:200px;background-image:url(/img/footer.jpg)">
</div>
</div>
</body>
</html>