HTML。ActionLink方法

Question

让我们说有一个类

public class ItemController:Controller
{
    public ActionResult Login(int id)
    {
        return View("Hi", id);
    }
}

在一个页面上是不是位于该项目的文件夹，里 ItemController 驻留，我希望创建一个链接到 Login 法。所以这 Html.ActionLink 方法，我应该使用哪些参数应当我通过吗？

具体地说，我正在寻找替代的方法

Html.ActionLink(article.Title,
    new { controller = "Articles", action = "Details",
          id = article.ArticleID })

已退休的在最近ASP.NET 视的化身。

Answer 1

我觉得你想要的是这个:

ASP.NET MVC1

Html.ActionLink(article.Title, 
                "Login",  // <-- Controller Name.
                "Item",   // <-- ActionMethod
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这将使用以下方法ActionLink签署：

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string controllerName,
                                string actionName,
                                object values, 
                                object htmlAttributes)

ASP.NET MVC2

两个论点已经被切换周围

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这将使用以下方法ActionLink签署：

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string actionName,
                                string controllerName,
                                object values, 
                                object htmlAttributes)

ASP.NET MVC3+

论据是相同的顺序MVC2，但是id价值不再是必需的：

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这样可以避免硬编码的任何路逻辑的链接。

 <a href="/Item/Login/5">Title</a> 

这会给你下面html输出，假设：

1. article.Title = "Title"
2. article.ArticleID = 5
3. 你还有下列路线的定义

. .

routes.MapRoute(
    "Default",     // Route name
    "{controller}/{action}/{id}",                           // URL with parameters
    new { controller = "Home", action = "Index", id = "" }  // Parameter defaults
);

Answer 2

我想添加到 Joseph Kingry的回答。他提供了解决方案，但起初我无法让它工作，并得到像Adhip Gupta一样的结果。然后我意识到路线必须首先存在，参数需要与路线完全匹配。所以我有一个id，然后是我的路线的文本参数，也需要包括在内。

Html.ActionLink(article.Title, "Login", "Item", new { id = article.ArticleID, title = article.Title }, null)

Answer 3

您可能需要查看 RouteLink() method.That允许您通过字典指定所有内容（链接文本和路由名称除外）。

Answer 4

我认为约瑟夫翻转了控制器和动作。首先是动作然后是控制器。这有点奇怪，但签名的样子。

为了澄清事情，这是有效的版本（改编约瑟夫的例子）：

Html.ActionLink(article.Title, 
    "Login",  // <-- ActionMethod
    "Item",   // <-- Controller Name
    new { id = article.ArticleID }, // <-- Route arguments.
    null  // <-- htmlArguments .. which are none
    )

Answer 5

这个怎么样

<%=Html.ActionLink("Get Involved", 
                   "Show", 
                   "Home", 
                   new 
                       { 
                           id = "GetInvolved" 
                       }, 
                   new { 
                           @class = "menuitem", 
                           id = "menu_getinvolved" 
                       }
                   )%>

Answer 6

Html.ActionLink(article.Title, "Login/" + article.ArticleID, 'Item") 

Answer 7

如果你想穿上所有的花式裤子，可以通过以下方式扩展它以便能够做到这一点：

@(Html.ActionLink<ArticlesController>(x => x.Details(), article.Title, new { id = article.ArticleID }))

您需要将其放在System.Web.Mvc命名空间中：

public static class MyProjectExtensions
{
    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController, TAction>(this HtmlHelper htmlHelper, Expression<Action<TController, TAction>> expression, string linkText, object routeValues)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText, object routeValues, object htmlAttributes) where TController : Controller
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var attributes = AnonymousObjectToKeyValue(htmlAttributes);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.MergeAttributes(attributes, true);
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    private static Dictionary<string, object> AnonymousObjectToKeyValue(object anonymousObject)
    {
        var dictionary = new Dictionary<string, object>();

        if (anonymousObject == null) return dictionary;

        foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(anonymousObject))
        {
            dictionary.Add(propertyDescriptor.Name, propertyDescriptor.GetValue(anonymousObject));
        }

        return dictionary;
    }
}

这包括Route Values和HTML Attributes的两个覆盖，以及您需要添加的所有视图：@using YourProject.Controllers或者您可以将其添加到web.config <pages><namespaces>

Answer 8

使用命名参数以提高可读性并避免混淆。

@Html.ActionLink(
            linkText: "Click Here",
            actionName: "Action",
            controllerName: "Home",
            routeValues: new { Identity = 2577 },
            htmlAttributes: null)

Answer 9

使用MVC5，我已经这样做了，它是100％正常工作的代码......

@Html.ActionLink(department.Name, "Index", "Employee", new { 
                            departmentId = department.DepartmentID }, null)

你们可以从中得到一个想法...

Answer 10

此类型使用：

@ Html.ActionLink（QUOT <！>;的MainPage QUOT <！>; <！>和quot;索引QUOT <！>; <！>和quot;首页QUOT <！>）

MainPage：文本名称 索引：动作视图 主页：HomeController

Base Use ActionLink

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>_Layout</title>
    <link href="@Url.Content("~/Content/bootsrap.min.css")" rel="stylesheet" type="text/css" />
</head>
<body>
    <div class="container">
        <div class="col-md-12">
            <button class="btn btn-default" type="submit">@Html.ActionLink("AnaSayfa","Index","Home")</button>
            <button class="btn btn-default" type="submit">@Html.ActionLink("Hakkımızda", "Hakkimizda", "Home")</button>
            <button class="btn btn-default" type="submit">@Html.ActionLink("Iletişim", "Iletisim", "Home")</button>
        </div> 
        @RenderBody()
        <div class="col-md-12" style="height:200px;background-image:url(/img/footer.jpg)">

        </div>
    </div>
</body>
</html>