MySQL的:获得“最忙”或“最流行的”小时从时间字段?
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20-09-2019 - |
题
考虑以下表,其具有的字段 - 编号(int)和DATE_CREATED(日期时间):
id date_created
1 2010-02-25 12:25:32
2 2010-02-26 13:40:37
3 2010-03-01 12:02:22
4 2010-03-01 12:10:23
5 2010-03-02 10:10:09
6 2010-03-03 12:45:03
我想知道一天中最忙/最受欢迎小时这组数据。在这个例子中,我正在寻找的结果将是12。
想法?
解决方案 4
我都喜欢西蒙和彼得的答案,但我不能同时选择所接受。我结合2,使清洁查询只返回的流行小时(我不需要计数)。
SELECT hour(date_created) AS h
FROM my_table
GROUP BY h
ORDER BY count(*) DESC
LIMIT 1
其他提示
要得到的只是最流行小时,使用此查询
select date_format( date_created, '%H' ) as `hour`
from [Table]
group by date_format( date_created, '%H' )
order by count(*) desc
limit 1;
如果你想看看所有的数据,去与这一个
select count(*) as num_records
, date_created
, date_format( date_created, '%H' ) as `hour`
from [Table]
group by `hour`
order by num_records desc;
如果你想要的东西多一点灵活的,也许是半小时或一刻钟,你可以做到以下几点:
SELECT floor(time_to_sec(date_created)/3600),count(*) AS period
FROM table GROUP BY period ORDER BY c DESC
如果您想要最流行的2小时间隔,使用7200最流行每隔15分钟,用900你只需要记住你是(在一小时3600秒)处理秒。
使用hour()
函数抽取小时,然后执行通常的聚合:
SELECT count(hour(date_created)) AS c, hour(date_created) AS h FROM table GROUP BY h ORDER BY c DESC;
您可以试试这个:
SELECT
DATE_FORMAT(date,'%H') as hours,
count(*) as count
FROM
myTable
GROUP BY
hours
ORDER BY
count DESC
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