如何操纵BY子句中的SQL类似于ORDER数组？

Question

我的数据已被放置到一个数组，但是在顺序不幸的是没有我想它在...

String[][] databaseToArray = {
  //{"Name", "Channel", "Description", "Amount", "isReady"},
    {"John", "Nick",    "likes",       "2",      "yes"    },
    {"Drew", "MTV",     "dislikes",    "4",      "no"     },
    {"Fred", "CNN",     "okay",        "3",      "no"     },
    {"Beth", "Fox",     "valid",       "1",      "yes"    }
};

如何操纵这一阵列，这样，当我通过它循环的顺序是由所述量，类似于SELECT * FROM "databaseToArray" ORDER BY "Amount"又名

String[][] reorganizedArray = {
  //{"Name", "Channel", "Description", "Amount", "isReady"},
    {"Beth", "Fox",     "valid",       "1",      "yes"    },
    {"John", "Nick",    "likes",       "2",      "yes"    },
    {"Fred", "CNN",     "okay",        "3",      "no"     },
    {"Drew", "MTV",     "dislikes",    "4",      "no"     }
};

Answer 1

您会想要一个比较传递给数组的.sort方法。我没有做过的Java 5年，但它应该是很容易做到的。也许有人能收拾这个例子中，我要写，因为我敢肯定我会得到了什么。

String[][] databaseToArray = {
  //{"Name", "Channel", "Description", "Amount", "isReady"},
    {"John", "Nick",    "likes",       "2",      "yes"    },
    {"Drew", "MTV",     "dislikes",    "4",      "no"     },
    {"Fred", "CNN",     "okay",        "3",      "no"     },
    {"Beth", "Fox",     "valid",       "1",      "yes"    }
};

Arrays.sort(databaseToArray, new Comparator<String[]>() {
    public int compare(String[] a, String[] b) {
        return a[3].compareTo(b[3]);
    }
});

Answer 2

我发现处理网站上的排序方法，但是这只是一维数组...

http://processing.org/reference/sort_.html

   float[] a = { 3, 5, 2, 4, 1 };
   a = sort(a);
   println(a);
// Prints 1, 2, 3, 4, 5