题
我可以通过编程方式设置WPF ListBox滚动条的位置吗?默认情况下,我希望它在中心。
解决方案
要在ListBox中移动垂直滚动条,请执行以下操作:
- 为列表框命名(x:Name =" myListBox")
- 为Window添加Loaded事件(Loaded =" Window_Loaded")
- 使用方法实现Loaded事件:ScrollToVerticalOffset 醇>
以下是一份工作样本:
XAML:
<Window x:Class="ListBoxScrollPosition.Views.MainView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Loaded="Window_Loaded"
Title="Main Window" Height="100" Width="200">
<DockPanel>
<Grid>
<ListBox x:Name="myListBox">
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
<ListBoxItem>Zamboni</ListBoxItem>
</ListBox>
</Grid>
</DockPanel>
</Window>
C#
private void Window_Loaded(object sender, RoutedEventArgs e)
{
// Get the border of the listview (first child of a listview)
Decorator border = VisualTreeHelper.GetChild(myListBox, 0) as Decorator;
if (border != null)
{
// Get scrollviewer
ScrollViewer scrollViewer = border.Child as ScrollViewer;
if (scrollViewer != null)
{
// center the Scroll Viewer...
double center = scrollViewer.ScrollableHeight / 2.0;
scrollViewer.ScrollToVerticalOffset(center);
}
}
}
其他提示
Dim cnt as Integer = myListBox.Items.Count
Dim midPoint as Integer = cnt\2
myListBox.ScrollIntoView(myListBox.Items(midPoint))
或
myListBox.SelectedIndex = midPoint
这取决于您是否想要显示或选择中间项目。
我刚刚更改了Zamboni的一些代码并添加了位置计算。
var border = VisualTreeHelper.GetChild(list, 0) as Decorator;
if (border == null) return;
var scrollViewer = border.Child as ScrollViewer;
if (scrollViewer == null) return;
scrollViewer.ScrollToVerticalOffset((scrollViewer.ScrollableHeight/list.Items.Count)*
(list.Items.IndexOf(list.SelectedItem) + 1));
我不认为ListBox有这个,但ListViews有 EnsureVisible 方法,将滚动条移动到所需位置,以确保显示项目。
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