题
我有这个 SELECT
声明:
SELECT SUM(dbo.DLData.Quantity)
FROM dbo.MasterDates
JOIN dbo.DLData ON MasterDates.[ID] = dbo.DLData.DownloadID
WHERE dbo.MasterDates.[Date] BETWEEN @From AND @To
AND dbo.MasterDates.SiteID = @X
如果你插 @From
, @To
和 @X
它的工作。这个是右手边的一个比较。但是在比较 @X
需要来自左手边的 SELECT
在外面是执行上的每一个测试 SiteID
在设定。没有这一条款的主要条款的工作。他们需要一起去。这里是完全的选择的发言与上述选择留。最终,这两个条款具有将确定的关键产品的网站。
--INSERT INTO SiteKeyProducts
SELECT dbo.MasterDates.SiteID as SiteID , dbo.DLData.Product as ProductID
FROM dbo.MasterDates
JOIN dbo.DLData ON dbo.MasterDates.[ID] = dbo.DLData.DownloadID
WHERE dbo.MasterDates.[Date] BETWEEN @From AND @To
GROUP BY dbo.MasterDates.SiteID , dbo.DLData.Product
HAVING
SUM(dbo.DLData.Quantity) > 960 OR
SUM(dbo.DLData.Quantity) > (SELECT SUM(dbo.DLData.Quantity)
FROM dbo.MasterDates
JOIN dbo.DLData ON MasterDates.[ID] = dbo.DLData.DownloadID
WHERE dbo.MasterDates.[Date] BETWEEN @From AND @To
AND dbo.MasterDates.SiteID = @X)
ORDER BY dbo.MasterDates.SiteID
你怎么使用外条款在内的声明吗? 该死,我甚至不知道如果我是使用正确的术语来描述我的问题。
Arrgghh设定基础的逻辑不我的头!
解决方案 2
马特*惠特菲尔德 在 问。sqlservercentral 回答#网站提出了以下答案 这个问题:
SELECT outerMaster.SiteID as SiteID , dbo.DLData.Product as ProductID
FROM dbo.MasterDates outerMaster
JOIN dbo.DLData ON outerMaster.[ID] = dbo.DLData.DownloadID
WHERE outerMaster.[Date] BETWEEN @From AND @To
GROUP BY outerMaster.SiteID , dbo.DLData.Product
HAVING
SUM(dbo.DLData.Quantity) > 960 OR
SUM(dbo.DLData.Quantity) > (SELECT SUM(dbo.DLData.Quantity)
FROM dbo.MasterDates innerMaster
JOIN dbo.DLData ON innerMaster.[ID] = dbo.DLData.DownloadID
WHERE innerMaster.[Date] BETWEEN @From AND @To
AND innerMaster.SiteID = outerMaster.SiteID)
ORDER BY outerMaster.SiteID
和 RickD 想出了这个答案的 ask.sqlteam.com 网站:
--INSERT INTO SiteKeyProducts
SELECT
MD.SiteID as SiteID ,
DLD.Product as ProductID
FROM dbo.MasterDates MD
JOIN dbo.DLData DLD
ON MD.[ID] = DLD.DownloadID
LEFT JOIN (SELECT SiteID,
SUM(dbo.DLData.Quantity) SumMDQuantity
FROM dbo.MasterDates
JOIN dbo.DLData ON MasterDates.[ID] = dbo.DLData.DownloadID
WHERE dbo.MasterDates.[Date] BETWEEN @From AND @To
GROUP BY SiteID) as sumMD
ON sumMD.SiteID = MD.SiteID
WHERE MD.[Date] BETWEEN @From AND @To
GROUP BY MD.SiteID , DLD.Product
HAVING
SUM(DLD.Quantity) > 960 OR
SUM(DLD.Quantity) > sumMD.SumMDQuantity
ORDER BY MD.SiteID
这两个伟大工作,虽然马特做好Ricks的努力,尽管我最初查看,参加将会更快。马特做需要-2m10时Ricks需要-2m40年代。这是最大的活数据库作为这两个时间不超过10秒的测试数据库。
其他提示
我想你想加入这个子查询,不具有语句中使用它
SELECT SUM(dbo.DLData.Quantity)
FROM dbo.MasterDates
JOIN dbo.DLData ON MasterDates.[ID] = dbo.DLData.DownloadID
WHERE dbo.MasterDates.[Date] BETWEEN @From AND @To
AND dbo.MasterDates.SiteID = @X
不隶属于 StackOverflow