如何使用FOR XML查询返回的SQL Server 2005/2008的列相同的子节点？

Question

基本上我需要从SQL Server表在下面的XML格式返回一些数据：

<querydata>
  <entity name="Person.Contact">
    <row>
      <field name="FirstName">Gustavo</field>
      <field name="LastName">Achong</field>
    </row>
    <row>
      <field name="FirstName">Catherine</field>
      <field name="LastName">Abel</field>
    </row>
...
  </entity>
</querydata>

我想出了下面的SQL语句：

select 'Person.Contact' as "@name", 
(select FirstName, LastName from Person.Contact for XML path('row'), TYPE)
for XML path('entity'), root('querydata')

哪些生成以下输出：

<querydata>
  <entity name="Person.Contact">
    <row>
      <FirstName>Gustavo</FirstName>
      <LastName>Achong</LastName>
    </row>
    <row>
      <FirstName>Catherine</FirstName>
      <LastName>Abel</LastName>
    </row>
....
  </entity>
</querydata>

但是我没有进一步得到。谢谢！

Answer 1

非常感谢你来抢！你一定让我在正确的轨道上，+1为您服务！我不得不换一个SELECT * FROM语句的一切，否则SQL服务器抱怨。这里是最终工作查询：

SELECT 'Person.Contact' as "@name",
(SELECT 
    (SELECT * from (SELECT 'FirstName' as [@name], [FirstName] as [*]
    union all
    SELECT 'LastName' as [@name], [LastName] as [*]) y
    for xml path('field'), TYPE)
from Person.Contact for XML path, TYPE)
for XML path('entity'), root('querydata')

Answer 2

您需要逆转置数据。

尝试使用子查询沿着线：

SELECT 'FirstName' as [@name], FirstName as [*]
union all
SELECT 'LastName' as [@name], LastName as [*]
for xml path('field')

或者沿着这些路线的东西...

我没有SQL与我（今天我的iPhone），但我对思维：

select 'Person.Contact' as "@name", 
(select (SELECT 'FirstName' as [@name], FirstName as [*]
union all
SELECT 'LastName' as [@name], LastName as [*]
for xml path('field')) from Person.Contact for XML path('row'), TYPE)
for XML path('entity'), root('querydata')