CF9 HQL语句对于很多一对多和多重标准

Question

我具有以下设置：

Listing.cfc

component persistent="true"
{
    property name="ListingId" column="ListingId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; 
        ...
    property name="Features" type="array" hint="Array of features" singularname="Feature" fieldtype="many-to-many" cfc="Feature" linktable="Listing_Feature" FKColumn="ListingId" inversejoincolumn="FeatureId";    
} 

Feature.cfc

component persistent="true" table="Feature" schema="dbo" output="false"
{
    property name="FeatureId" column="FeatureId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; 
    property name="FeatureDescription" column="FeatureDescription" type="string" ormtype="string";
    ...    
    /*property name="Listings" fieldtype="many-to-many" cfc="Listing" linktable="Listing_Feature" fkcolumn="FeatureId" inversejoincolumn="ListingId" lazy="true" cascade="all" orderby="GroupOrder";*/

} 

我可以选择使用具有特定特征的所有目录：

<cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId = :feature",{feature = 110}) />

这很好，不过，我希望能够选择具有多种功能的所有目录（例如上市同时具有“厨房”和“车库”）

在谷歌上搜索，并通过Hibernate文档看的几个小时一直没能找到，不会给我一个错误的解决方案。我的猜测是，该解决方案是非常简单的，我只是过于思前想...任何人有什么建议？

Answer 1

我不相信这是做到这一点的最有效的方法，但是，它会产生我想

结果

<cfset matchingListings = ormExecuteQuery("Select l.ListingId from Listing l
  left join l.Features as featureone left join l.Features as featuretwo
  left join l.Features as featurethree 
  where featureone.FeatureId = 108
    and featuretwo.FeatureId = 110
    and featurethree.FeatureId = 113") />

这会给我只有具备的所有功能，我在寻找，但是，它确实加盟，看着休眠SQL日志中产生的大量上市：

select listing0_.ListingId as col_0_0_ 
from dbo.Listing listing0_ 
left outer join Listing_Feature features1_ on listing0_.ListingId=features1_.ListingId 
left outer join dbo.Feature feature2_ on features1_.FeatureId=feature2_.FeatureId
left outer join Listing_Feature features3_ on listing0_.ListingId=features3_.ListingId 
left outer join dbo.Feature feature4_ on features3_.FeatureId=feature4_.FeatureId 
left outer join Listing_Feature features5_ on listing0_.ListingId=features5_.ListingId 
left outer join dbo.Feature feature6_ on features5_.FeatureId=feature6_.FeatureId 
where 1=1 
and feature2_.FeatureId=108 
and feature4_.FeatureId=110 
and feature6_.FeatureId=113

这似乎只是必须有HQL这样做更有效的方式。

---

乔恩·梅塞尔的CF-ORM-dev邮件列表上给了我什么，我相信是最正确的解决这个问题张贴在这里给大家：

“据我所知ORMExecuteQuery不处理列表参数，所以如果你想PARAM他们返回对象，你不得不这样做。

<cfset featureIds = [javaCast('int',108), javaCast('int',110), javaCast('int',113)] >

<cfset q = ormGetSession().createQuery("
    select l.ListingId 
    from Listing l 
        join l.features as f 
    where f.FeatureId in (:features)
    group by l.ListingId
    having count(*) = #arrayLen(featureIds)#
") /> 

<cfset q.setParameterList('features', featureIds) /> 

<cfset matchingListings = q.list() />

“

感谢乔恩！

Answer 2

此应该工作：

<cfset featurelist = "110,113,125"/>
<cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId IN (#featurelist#)")/>

如果你想要去的，你将不得不做一些额外的工作绑定参数，因为Hibernate不喜欢ColdFusion的列表和/或数组作为绑定参数这个时候。你可以找到一些额外的信息这里