产生的页码使用javascript级?
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22-09-2019 - |
题
如何产生的页面数字的下使用javascript级?
如果第5页选我必须显示3、4和6、7和也1,最后一页,与上一个,接下来...任何建议。...
编辑:
如何工作和协调结果的方式的数据,使用这些分页div?(e)我java包含50记录 我想在10第1页。如何分java与这些数字...
我想要一个jquery功能通过 currentpageno,lastpagenumber
与功能应该产生我页数字下面的我
如果是第一页
如果是在中间,
如果这是最后一页
第二编辑:
我已经尝试这一功能,但似乎并没有得到期望的结果
function generatePages(currentPage, LastPage) {
if (LastPage <= 5) {
var pages = '';
for(var i=1;i<=5;i++)
{
pages += "<a class='page-numbers' href='#'>" + i + "</a>"
}
$("#PagerDiv").append(pages);
}
if (LastPage > 5) {
var pages = '';
for (var i = 1; i <= 5; i++) {
pages += "<a class='page-numbers' href='#'>" + i + "</a>"
}
$("#PagerDiv").append(pages);
}
}
我 lastPage
和 currentPage
值,请帮帮我得到这个...
解决方案
您正在寻找被称为“分页”和什么有(总是)一个jQuery插件,没有工作适合你:
http://d-scribe.de/webtools/jquery-分页/演示/ demo_options.htm
(下载它 rel="noreferrer">这里)
编辑:因为你似乎没有能够得到它的工作,这里是单向的(几个不同的),您可以如何使用插件
<强>步骤1:强>从JSON数据像下面生成标记:
<div id="display">
<!-- This is the div where the visible page will be displayed -->
</div>
<div id="hiddenData">
<!-- This is the div where you output your records -->
<div class="record">
<!-- create one record-div for each record you have in your JSON data -->
</div>
<div class="record">
</div>
</div>
的想法是一个页链接上点击时,各自的记录复制到所述显示格。因此,该插件提供一个pageSelect回调函数。的步骤2 强>是为了实现该功能,例如:
function pageselectCallback(pageIndex, jq){
// Clone the record that should be displayed
var newContent = $('#hiddenData div.record:eq('+pageIndex+')').clone();
// Update the display container
$('#display').empty().append(newContent);
return false;
}
这将意味着你必须记录每一个页面。如果你想每页显示多条记录,你必须相应地修改上述功能。
<强>第三和最后的步骤强>是正确初始化整个事情。
function initPagination() {
// Hide the records... they shouldn't be displayed
$("#hiddenData").css("display", "none");
// Get the number of records
var numEntries = $('#hiddenData div.result').length;
// Create pagination element
$("#pagination").pagination(numEntries, {
num_edge_entries: 2,
num_display_entries: 8, // number of page links displayed
callback: pageselectCallback,
items_per_page: 1 // Adjust this value if you change the callback!
});
}
所以,你只需要事后从您的JSON数据生成的HTML标记,并调用init-功能。
这并不难,不是吗?
其他提示
耶@SLaks是正确的。没有什么太疯狂了这里。您将有2个变量currentPageNumber和lastPageNumber。
$("div.paginator").append("<a...>prev</a>");
$("div.paginator").append("<a...>1</a>");
for (x = (currentPageNumber - 2; x <= (currentPageNumber + 2); x++) {
$("div.paginator").append("<a...>"+ x +"</a>");
}
$("div.paginator").append("<a...>"+ lastPageNumber +"</a>");
$("div.paginator").append("<a...>next</a>");
// you could apply styles to and a tag in the div.paginator
// you could apply a special class to the a tag that matches the currentPageNumber
// you can also bind some click events to each a tag and use the $(this).text() to grab the number of the page to go to
...添加两个新的隐藏的输入
<input type='hidden' id='current_page' />
<input type='hidden' id='show_per_page' />
接着添加一个空div来创建分页控件
<!-- An empty div which will be populated using jQuery -->
<div id='page_navigation'></div>
$(document).ready(function(){
//how much items per page to show
var show_per_page = 5;
//getting the amount of elements inside content div
var number_of_items = $('#content').children().size();
//calculate the number of pages we are going to have
var number_of_pages = Math.ceil(number_of_items/show_per_page);
//set the value of our hidden input fields
$('#current_page').val(0);
$('#show_per_page').val(show_per_page);
//now when we got all we need for the navigation let's make it '
/*
what are we going to have in the navigation?
- link to previous page
- links to specific pages
- link to next page
*/
var navigation_html = '<a class="previous_link" href="javascript:previous();">Prev</a>';
var current_link = 0;
while(number_of_pages > current_link){
navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';
current_link++;
}
navigation_html += '<a class="next_link" href="javascript:next();">Next</a>';
$('#page_navigation').html(navigation_html);
//add active_page class to the first page link
$('#page_navigation .page_link:first').addClass('active_page');
//hide all the elements inside content div
$('#content').children().css('display', 'none');
//and show the first n (show_per_page) elements
$('#content').children().slice(0, show_per_page).css('display', 'block');
});
function previous(){
new_page = parseInt($('#current_page').val()) - 1;
//if there is an item before the current active link run the function
if($('.active_page').prev('.page_link').length==true){
go_to_page(new_page);
}
}
function next(){
new_page = parseInt($('#current_page').val()) + 1;
//if there is an item after the current active link run the function
if($('.active_page').next('.page_link').length==true){
go_to_page(new_page);
}
}
function go_to_page(page_num){
//get the number of items shown per page
var show_per_page = parseInt($('#show_per_page').val());
//get the element number where to start the slice from
start_from = page_num * show_per_page;
//get the element number where to end the slice
end_on = start_from + show_per_page;
//hide all children elements of content div, get specific items and show them
$('#content').children().css('display', 'none').slice(start_from, end_on).css('display', 'block');
/*get the page link that has longdesc attribute of the current page and add active_page class to it
and remove that class from previously active page link*/
$('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page');
//update the current page input field
$('#current_page').val(page_num);
}