Android的JSON HttpClient的将数据发送到PHP服务器的HttpResponse

Question

目前我正在试图从和Android应用程序发送一些数据到PHP服务器（两者都是由我控制）。

有很多是收集在该应用中的窗体上的数据，这被写入到数据库中。此工作的。

在我的主代码中，首先创建一个JSONObject（我剪下来这里用于本示例）：

JSONObject j = new JSONObject();
j.put("engineer", "me");
j.put("date", "today");
j.put("fuel", "full");
j.put("car", "mine");
j.put("distance", "miles");

接下来，我传递对象上用于发送和接收响应：

String url = "http://www.server.com/thisfile.php";
HttpResponse re = HTTPPoster.doPost(url, j);
String temp = EntityUtils.toString(re.getEntity());
if (temp.compareTo("SUCCESS")==0)
{
    Toast.makeText(this, "Sending complete!", Toast.LENGTH_LONG).show();
}

在HTTPPoster类：

public static HttpResponse doPost(String url, JSONObject c) throws ClientProtocolException, IOException 
{
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost request = new HttpPost(url);
    HttpEntity entity;
    StringEntity s = new StringEntity(c.toString());
    s.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
    entity = s;
    request.setEntity(entity);
    HttpResponse response;
    response = httpclient.execute(request);
    return response;
}

此产生响应，但服务器返回一个403 - 禁止响应

我试图改变所述的doPost功能一点（这其实是一个好一点，正如我所说我有很多要发送时，基本上3相同的形式具有不同的数据 - 所以我创建3和一个JSONObjects，每个表格条目 - 条目来自DB代替我使用的静态示例）

。

首先我改变该呼叫通过位：

String url = "http://www.myserver.com/ServiceMatalan.php";
Map<String, String> kvPairs = new HashMap<String, String>();
kvPairs.put("vehicle", j.toString());
// Normally I would pass two more JSONObjects.....
HttpResponse re = HTTPPoster.doPost(url, kvPairs);
String temp = EntityUtils.toString(re.getEntity());
if (temp.compareTo("SUCCESS")==0)
{
    Toast.makeText(this, "Sending complete!", Toast.LENGTH_LONG).show();
}

确定这样的更改的doPost功能：

public static HttpResponse doPost(String url, Map<String, String> kvPairs) throws ClientProtocolException, IOException 
{
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url);
    if (kvPairs != null && kvPairs.isEmpty() == false) 
    {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(kvPairs.size());
        String k, v;
        Iterator<String> itKeys = kvPairs.keySet().iterator();
        while (itKeys.hasNext()) 
        {
            k = itKeys.next();
            v = kvPairs.get(k);
            nameValuePairs.add(new BasicNameValuePair(k, v));
        }             
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    }
    HttpResponse response;
    response = httpclient.execute(httppost);
    return response;
}

行，所以这返回响应200

int statusCode = re.getStatusLine().getStatusCode();

但是在服务器上接收到的数据不能被解析到一个JSON字符串。据格式错误，我认为（这是第一次我已经使用JSON）：

如果在php文件I上$ _POST [ '车辆']做的回波，得到类似如下：

{\"date\":\"today\",\"engineer\":\"me\"}

谁能告诉我在哪里，我错了，或者如果有更好的方法来实现什么，我试图做的？希望上面很有意义！

Answer 1

经过大量的阅读和搜索我已经发现这个问题，我beleive在服务器上启用magic_quotes_gpc的幸福。

因此，使用：

json_decode(stripslashes($_POST['vehicle']));

在我的例子上述去除斜线并允许JSON来正确解码。

仍然不知道为什么发送StringEntity导致403错误？

Answer 2

StringEntity s = new StringEntity(c.toString());
s.setContentEncoding("UTF-8");
s.setContentType("application/json");
request.setEntity(s);

Answer 3

试试这个代码，它为我的作品

public void postData(String result,JSONObject obj) {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpParams myParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(myParams, 10000);
HttpConnectionParams.setSoTimeout(myParams, 10000);

String json=obj.toString();

try {

    HttpPost httppost = new HttpPost(result.toString());
    httppost.setHeader("Content-type", "application/json");

    StringEntity se = new StringEntity(obj.toString()); 
    se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
    httppost.setEntity(se); 

    HttpResponse response = httpclient.execute(httppost);
    String temp = EntityUtils.toString(response.getEntity());
    Log.i("tag", temp);


} catch (ClientProtocolException e) {

} catch (IOException e) {
}

}

Answer 4

更改

(String url = "http://www.server.com/MainPage.php";)

到

(String url = "http://www.server.com/MainPage.php?";)

当你试图参数发送到PHP脚本末问号是必要的。

Answer 5

<强>尝试此代码它完美

*For HttpClient class* download jar file "httpclient-4.3.6.jar" and put in libs folder then
Compile:   dependencies {compile files('libs/httpclient-4.3.6.jar')}

repositories {
        maven {
            url "https://jitpack.io"
        }
    }