hist.get(i, 0) returns array of doubles. So you can try this:
for (int i = 0; i< 25; i++) {
double[] histValues = hist.get(i, 0);
for (int j = 0; j < histValues.length; j++) {
Log.d(TAG, "yourData=" + histValues[j]);
}
}
题
i am working on an android project using opencv , i am creating a histogram for a black and white image (1-0 values on image file) . i am following some tutorials i found on internet on how to create the histogram . i am doing something like this
ArrayList<Mat> list = new ArrayList<Mat>();
list.add(mRgba);
MatOfInt channels = new MatOfInt(0);
Mat hist= new Mat();
MatOfInt histSize = new MatOfInt(25);
MatOfFloat ranges = new MatOfFloat(0f, 1f);
Imgproc.calcHist(list, channels, new Mat(), hist, histSize, ranges);
Then i want to view the data on hist Mat, if i try something like this...
for(int i = 0;i<25;i++){
Log.e(TAG, "data "+i+" "+hist.get(i, 0));
}
i get
> data 0 [D@2be05908
data 1 [D@2be0a138
data 2 [D@2bdf9f48
data 22 [D@2be06c70
that makes no sense to me. if i try a different approach, like
byte buff[] = new byte[ hist.height()*hist.width() * hist.channels()];
hist.get(0, 0, buff);
i get error about mat compatibility with mat.get function.
Is there any way to directly access the data on hist mat?
i am intrested in getting back all the data, not only man mix
解决方案
hist.get(i, 0) returns array of doubles. So you can try this:
for (int i = 0; i< 25; i++) {
double[] histValues = hist.get(i, 0);
for (int j = 0; j < histValues.length; j++) {
Log.d(TAG, "yourData=" + histValues[j]);
}
}