题
<强>我使用以下代码打开的货架:强>
#!/usr/bin/python
import shelve #Module:Shelve is imported to achieve persistence
Accounts = 0
Victor = {'Name':'Victor Hughes','Email':'victor@yahoo.com','Deposit':65000,'Accno':'SA456178','Acctype':'Savings'}
Beverly = {'Name':'Beverly Dsilva','Email':'bevd@hotmail.com','Deposit':23000,'Accno':'CA432178','Acctype':'Current'}
def open_shelf(name='shelfile.shl'):
global Accounts
Accounts = shelve.open(name) #Accounts = {}
Accounts['Beverly']= Beverly
Accounts['Victor']= Victor
def close_shelf():
Accounts.close()
我能够追加值的货架,但无法修改的值。 的我已经定义了一个函数存款(),从该我想修改数据存在于shelve.But它给我以下错误:强>
Traceback (most recent call last):
File "./functest.py", line 16, in <module>
Deposit()
File "/home/pavitar/Software-Development/Python/Banking/Snippets/Depositfunc.py", line 18, in Deposit
for key in Accounts:
TypeError: 'int' object is not iterable
<强>这是我的功能:强>
#!/usr/bin/python
import os #This module is imported so as to use clear function in the while-loop
from DB import * #Imports the data from database DB.py
def Deposit():
while True:
os.system("clear") #Clears the screen once the loop is re-invoked
input = raw_input('\nEnter the A/c type: ')
flag=0
for key in Accounts:
if Accounts[key]['Acctype'].find(input) != -1:
amt = input('\nAmount of Deposit: ')
flag+=1
Accounts[key]['Deposit'] += amt
if flag == 0:
print "NO such Account!"
if __name__ == '__main__':
open_shelf()
Deposit()
close_shelf()
我是新来Python.Please help.Correct我,如果我wrong.I需要别人给的解释,这code.I'm的运作有点混淆。
解决方案
首先,不使用全球对Accounts
,而通过来回。使用全球造成的错误。像这样:
def open_shelf(name='shelfile.shl'):
Accounts = shelve.open(name) #Accounts = {}
...
return Accounts
def close_shelf(Accounts):
Accounts.close()
def Deposit(Accounts):
...
if __name__ == '__main__':
Accounts = open_shelf()
Deposit(Accounts)
close_shelf(Accounts)
其次,不重新定义的内置函数。在Deposit()
,你raw_input
的结果分配给一个名为input
变量:
input = raw_input('\nEnter the A/c type: ')
四大行后,您尝试使用内置的input
功能:
amt = input('\nAmount of Deposit: ')
但是,这不会工作,因为input
已经被重新定义!
第三,当迭代过搁置物品,按照1)抓斗搁置物品的图案,2)发生变异项,3)写突变项回搁板。像这样:
for key, acct in Accounts.iteritems(): # grab a shelved item
if val['Acctype'].find(input) != -1:
amt = input('\nAmount of Deposit: ')
flag+=1
acct['Deposit'] += amt # mutate the item
Accounts[key] = acct # write item back to shelf
(建议的该第三位是从 hughdbrown 的回答微调。)
其他提示
我觉得你有更多的运气是这样的:
for key, val in Accounts.iteritems():
if val['Acctype'].find(input) != -1:
amt = input('\nAmount of Deposit: ')
flag+=1
val['Deposit'] += amt
Accounts[key] = val
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