Hibernate如何能够处理重叠的外键？

Question

我有一个具有两个外键到两个不同的表与两个外键的表共享一列：

CREATE TABLE ZipAreas
(
  country_code CHAR(2) NOT NULL,
  zip_code VARCHAR(10) NOT NULL,
  state_code VARCHAR(5) NOT NULL,
  city_name VARCHAR(100) NOT NULL,
  PRIMARY KEY (country_code, zip_code, state_code, city_name),
  FOREIGN KEY (country_code, zip_code) REFERENCES Zips (country_code, code),
  FOREIGN KEY (country_code, state_code, city_name) REFERENCES Cities (country_code, state_code, name)
)

可以看到，有两个共享FKS COUNTRY_CODE（巧合引用在referentiation路径的端部相同的列）。实体类看起来像（JPA 1.0 @IdClass）：

@Entity
@Table(name = "ZipAreas")
@IdClass(value = ZipAreaId.class)
public class ZipArea implements Serializable
{
    @Id
    @Column(name = "country_code", insertable = false, updatable = false)
    private String countryCode;

    @Id
    @Column(name = "zip_code", insertable = false, updatable = false)
    private String zipCode;

    @Id
    @Column(name = "state_code", insertable = false, updatable = false)
    private String stateCode;

    @Id
    @Column(name = "city_name", insertable = false, updatable = false)
    private String cityName;

    @ManyToOne
    @JoinColumns(value = {@JoinColumn(name = "country_code", referencedColumnName = "country_code"), @JoinColumn(name = "zip_code", referencedColumnName = "code")})
    private Zip zip = null;

    @ManyToOne
    @JoinColumns(value = {@JoinColumn(name = "country_code", referencedColumnName = "country_code", insertable = false, updatable = false), @JoinColumn(name = "state_code", referencedColumnName = "state_code"), @JoinColumn(name = "city_name", referencedColumnName = "name")})
    private City city = null;

    ...
}

正如你可以看到我举报的COUNTRYCODE财产和城市的COUNTRY_CODE @JoinColumn为只读（插入=假，可更新=假）。休眠失败，此说法：

Exception in thread "main" javax.persistence.PersistenceException: [PersistenceUnit: geoinfo] Unable to configure EntityManagerFactory
    at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:374)
    at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:56)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:48)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32)
    at tld.geoinfo.Main.main(Main.java:27)
Caused by: org.hibernate.AnnotationException: Mixing insertable and non insertable columns in a property is not allowed: tld.geoinfo.model.ZipAreacity
    at org.hibernate.cfg.Ejb3Column.checkPropertyConsistency(Ejb3Column.java:563)
    at org.hibernate.cfg.AnnotationBinder.bindManyToOne(AnnotationBinder.java:2703)
    at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1600)
    at org.hibernate.cfg.AnnotationBinder.processIdPropertiesIfNotAlready(AnnotationBinder.java:796)
    at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:707)
    at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3977)
    at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3931)
    at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1368)
    at org.hibernate.cfg.Configuration.buildMappings(Configuration.java:1345)
    at org.hibernate.ejb.Ejb3Configuration.buildMappings(Ejb3Configuration.java:1477)
    at org.hibernate.ejb.EventListenerConfigurator.configure(EventListenerConfigurator.java:193)
    at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:1096)
    at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:278)
    at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:362)
    ... 4 more

这看起来很基本的对我说实话。 “在属性混合插入和非插入列是不允许的”是这样的弱“的理由”，是吗？

Hibernate如何能够处理这一点，例如根据JPA规范？这是一个错误？

Answer 1

将与休眠5被支持，请参阅 https://hibernate.atlassian.net/browse / HHH-6221

Answer 2

有一种方法来绕过验证和得到它的工作，从而指示该列是“@JoinColumnsOrFormulas”然后把溶液：

错误：

@ManyToOne
@JoinColumns(value = {
    @JoinColumn(name = "country_code", referencedColumnName = "country_code"), 
    @JoinColumn(name = "zip_code", referencedColumnName = "code")})
private Zip zip = null;

@ManyToOne
@JoinColumns(value = {
    @JoinColumn(name = "country_code", referencedColumnName = "country_code", insertable = false, updatable = false),
    @JoinColumn(name = "state_code", referencedColumnName = "state_code"), 
    @JoinColumn(name = "city_name", referencedColumnName = "name")})
private City city = null;

行：

@ManyToOne
@JoinColumns(value = {
    @JoinColumn(name = "country_code", referencedColumnName = "country_code"), 
    @JoinColumn(name = "zip_code", referencedColumnName = "code")})
private Zip zip = null;

@ManyToOne
@JoinColumnsOrFormulas(value = {
    @JoinColumnOrFormula(formula = @JoinFormula(value = "country_code", referencedColumnName = "country_code")),
    @JoinColumnOrFormula(column = @JoinColumn(name = "state_code", referencedColumnName = "state_code")),
    @JoinColumnOrFormula(column = @JoinColumn(name = "city_name", referencedColumnName = "name"))
})
private City city = null;

此致

Answer 3

我使用休眠5，我仍然得到这个例外。如果添加插入=“假”，更新=“假”只有一个，你会得到一个异常，说明你混合插入式和非插入列，这是不允许的。这是一个已经在跟踪一个问题，但似乎并没有得到解决。 休眠抛出上柱AnnotationException由多个重叠的外键

用于

在我们的例子中，这意味着我们迁移到EclipseLink的，这实际上是很容易给你主要是需要更换persistence.xml并重写HSQL（Hibernate的SQL），以JPQL（JPA SQL）。您可能还需要更换自定义的命名策略（Eclipse中称他们SessionCustomizer）。当然，这可能是更难，因为Hibernate Search的等等。但在我们的例子中，我们试图解决重叠的外键数周，当迁移只用了几个小时在做到底，如果你用hibernate这样的特殊功能。

Answer 4

这仍然不处于休眠5解决。 但是，如果我用@JoinColumnsOrFormulas我得到ClassCastException异常。 在所有连接列追加insertable = false, updatable = false解决我的问题：

示例：

@ManyToOne
@JoinColumns(value = {
    @JoinColumn(name = "country_code", referencedColumnName = "country_code", insertable = false, updatable = false),
    @JoinColumn(name = "state_code", referencedColumnName = "state_code", insertable = false, updatable = false), 
    @JoinColumn(name = "city_name", referencedColumnName = "name", insertable = false, updatable = false)})
private City city = null;