德尔福ODAC:从Oracle AQ Disecting JMS消息
-
27-09-2019 - |
题
我试图评估ODAC使用Oracle AQ。 请求队列包含JMS对象喜欢这些(但没有换行符和其他空白):
SYS.AQ$_JMS_BYTES_MESSAGE(
SYS.AQ$_JMS_HEADER(
'null','null','null','null','null','null',
SYS.AQ$_JMS_USERPROPARRAY(
SYS.AQ$_JMS_USERPROPERTY('Key1',100,'Value1','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key2',100,'Value2','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key3',100,'Value3','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key4',100,'Value4','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key5',100,'Value5','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key6',100,'Value6','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key7',100,'Value7','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key8',100,'Value8','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key9',100,'Value9','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key10',100,'Value10.0','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key11',100,'Value11','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key12',100,'Value12','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key13',100,'Value13','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key14',100,'Value14','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key15',100,'Value15','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key16',100,'Value16','null',27),
SYS.AQ$_JMS_USERPROPERTY('Key17',100,'Value17','null',27)
)
),
4168,'null','oracle.sql.BLOB@959acc'
)
可以接收底层对象(一个字符串净荷回来为一个空字符串,而是一个TOraObject有效载荷包含的数据)。
我想disscect的TOraObject有效载荷,并且正在寻找一个表中的数据类型值转换成正确的AttrXxxx [name]属性的电话。
OraType.AttributeCount:4
OraType.Name:"SYS"."AQ$_JMS_BYTES_MESSAGE"
OraType.DataType:15
Attribute[0].Name:HEADER
Attribute[0].DataType:15
OraType.AttributeCount:7
OraType.Name:"SYS"."AQ$_JMS_HEADER"
OraType.DataType:15
Attribute[0].Name:REPLYTO
Attribute[0].DataType:15
OraType.AttributeCount:3
OraType.Name:"SYS"."AQ$_AGENT"
OraType.DataType:15
Attribute[0].Name:NAME
Attribute[0].DataType:1
Attribute[1].Name:ADDRESS
Attribute[1].DataType:1
Attribute[2].Name:PROTOCOL
Attribute[2].DataType:5
Attribute[1].Name:TYPE
Attribute[1].DataType:1
Attribute[2].Name:USERID
Attribute[2].DataType:1
Attribute[3].Name:APPID
Attribute[3].DataType:1
Attribute[4].Name:GROUPID
Attribute[4].DataType:1
Attribute[5].Name:GROUPSEQ
Attribute[5].DataType:5
Attribute[6].Name:PROPERTIES
Attribute[6].DataType:17
OraType.AttributeCount:1
OraType.Name:"SYS"."AQ$_JMS_USERPROPARRAY"
OraType.DataType:17
Attribute[0].Name:ELEMENT
Attribute[0].DataType:15
OraType.AttributeCount:5
OraType.Name:"SYS"."AQ$_JMS_USERPROPERTY"
OraType.DataType:15
Attribute[0].Name:NAME
Attribute[0].DataType:1
Attribute[1].Name:TYPE
Attribute[1].DataType:5
Attribute[2].Name:STR_VALUE
Attribute[2].DataType:1
Attribute[3].Name:NUM_VALUE
Attribute[3].DataType:5
Attribute[4].Name:JAVA_TYPE
Attribute[4].DataType:5
Attribute[1].Name:BYTES_LEN
Attribute[1].DataType:5
Attribute[2].Name:BYTES_RAW
Attribute[2].DataType:1
Attribute[3].Name:BYTES_LOB
Attribute[3].DataType:102
通过试验和错误,我来迄今:
case DataType of
102:
LOB := ObjectPayLoad.AttrAsLob[Name];
15:
AttributeOraObject := ObjectPayLoad.AttrAsObject[Name];
17:
AttributeOraArray := ObjectPayLoad.AttrAsArray[Name];
else
begin
PayLoadAttributeAsString := ObjectPayLoad. AttrAsString[Name];
Logger.Log(' "%s"', [PayLoadAttributeAsString]);
end;
end;
一个更完整的列表是受欢迎的: - )
在此之后,我将需要研究周围的其他方式:产生中有一个JMS内容的权利TOraObject。 对于那些还提示欢迎。
- 的Jeroen
解决方案
修改强>
ODAC 具有限定常量多个单元。结果
恒定dtOraBlob
与值102处于OraClasses
单元;限定数据类型值的常数与前缀dt
定义它们开始,而不管单元。
<强>原始强>
我已经发现在MemData
单元几这些常数的:
case DataType of
102:
LOB := OraObject.AttrAsLob[Name];
MemData.dtObject: // 15
begin
AttributeOraObject := OraObject.AttrAsObject[Name];
LogOraObject(AttributeOraObject, Level+1);
end;
MemData.dtArray: // 17
begin
AttributeOraArray := OraObject.AttrAsArray[Name];
LogOraArray(AttributeOraArray, Level);
end;
MemData.dtFloat: // 5
begin
AttributeFloat := OraObject.AttrAsFloat[Name];
Logger.Log(Prefix+'"%g"', [AttributeFloat]);
end;
MemData.dtString: // 1
begin
PayLoadAttributeAsString := OraObject.AttrAsString[Name];
Logger.Log(Prefix+'"%s"', [PayLoadAttributeAsString]);
end;
else
begin
PayLoadAttributeAsString := OraObject.AttrAsString[Name];
Logger.Log(Prefix+'"%s"', [PayLoadAttributeAsString]);
end;
end;
我无法找到102恒定的,虽然,但我敢肯定它是一个LOB字段。
任何人谁可以证实?
- 的Jeroen
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