我用什么代替e.Values.add（＆＃8230;用于ListViewEditEventArgs上传图片

Question

我可以在为ListViewInsertEventArgs重新设计e.Values方法时使用linq和listview控件将图像上传到数据库，但ListViewEditEventArgs中没有这样的方法，那么我可以使用什么来获得相同的结果？

这是我的插入代码：

protected void ProjectPhotosList_ItemInserting（object sender，ListViewInsertEventArgs e）

{

FileUpload uplImage =（FileUpload）ProjectPhotosList.InsertItem.FindControl（＆quot; uplImage＆quot;）;

标签fileuploadlbl =（标签）ProjectPhotosList.InsertItem.FindControl（＆quot; fileuploadlbl＆quot;）;

    byte[] img = null;
    if (uplImage.HasFile || !uplImage.FileName.ToLower().EndsWith(".jpg"))
    {
        try
        {
            img = new byte[uplImage.PostedFile.ContentLength];
            uplImage.PostedFile.InputStream.Read(img, 0, img.Length);
        }
        catch
        {
            fileuploadlbl.Text = "unable to upload " + uplImage.FileName.ToString();
        }
    }
    if (img == null)
    {
        e.Cancel = true;
        fileuploadlbl.Text = "Please choose a file to upload";
    }

    try
    {
        e.Values.Add("ProjectPhoto", new System.Data.Linq.Binary(img));
        fileuploadlbl.Text = "File Upload Successful";
    }
    catch
    {
        fileuploadlbl.Text = "File Upload Failed, please try again";
    }
}

Answer 1

好的，所以我已经解决了这个问题！我只是不得不采取一些不同的方式：

这是重要的代码：

int mykey = int.Parse（ProjectPhotosList.DataKeys [e.ItemIndex] .Value.ToString（））;

它只是获取所选行的primarykey值的简单方法。 我发现了一篇关于将pdf上传到数据库的帖子，并决定将其余的代码基于此。所以这里是完整的代码：

protected void ProjectPhotosList_ItemUpdating（object sender，ListViewUpdateEventArgs e）

{

FileUpload myFile =（FileUpload）ProjectPhotosList.EditItem.FindControl（＆quot; uploadImage＆quot;）;

    TextBox myCaption = (TextBox)ProjectPhotosList.EditItem.FindControl("ProjectPhotoCaptionTextBox");

    int mykey = int.Parse(ProjectPhotosList.DataKeys[e.ItemIndex].Value.ToString());

    if (myFile.HasFile)
    {

        //Get the posted file
        Stream fileDataStream = myFile.PostedFile.InputStream;

        //Get length of file
        int fileLength = myFile.PostedFile.ContentLength;

        //Create a byte array with file length
        byte[] fileData = new byte[fileLength];

        //Read the stream into the byte array
        fileDataStream.Read(fileData, 0, fileLength);

        //get the file type
        string fileType = myFile.PostedFile.ContentType;

        //Open Connection
        PHJamesDataContext db = new PHJamesDataContext();
        //Find the Right Row
        PHJProjectPhoto Newphoto = (from p in db.PHJProjectPhotos
                                    where p.ProjectPhotoId == mykey
                                    select p).Single<PHJProjectPhoto>();


        Newphoto.ProjectPhoto = fileData;

        db.SubmitChanges();
    }