++ I + ++ I + ++ i??Java??C?
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28-09-2019 - |
题
int i=2;
i = ++i + ++i + ++i;
???????? 12?C = 13,??,?????????Java???,??????
解决方案
There is nothing like more correct. It is actually undefined and its called Sequence Point Error. http://en.wikipedia.org/wiki/Sequence_point
其他提示
Java guarantees (§15.7.1) that it will be evaluated left-to-right, giving 12. Specifically, ++
has higher precedence that +
. So it first binds those, then it associates the addition operations left to right
i = (((++i) + (++i)) + (++i));
§15.7.1 says the left operand is evaluated first, and §15.7.2 says both operands are evaluated before the operation. So it evaluates like:
i = (((++i) + (++i)) + (++i));
i = ((3 + (++i)) + (++i)); // i = 3;
i = ((3 + 4) + (++i)); // i = 4;
i = (7 + (++i)); // i = 4;
i = (7 + 5); // i = 5;
i = 12;
In C, it is undefined behavior to modify a variable twice without a sequence point in between.
The Java result makes sense to me because the operators give the result you would expect, but no serious program should contain a statement like this.
EDIT: I'm amused that this one sentence response has been my highest scored answer of the evening (compared to the dozen other answers I posted, some with pages of code samples). Such is life.
In C this is undefined behavior. There is no correct behavior.