为什么这个LEFT JOIN在其他表中没有任何内容消除记录？

Question

我有一个MySQL Left Join问题。

我有三张桌子，我正在尝试加入。

人员表：

CREATE TABLE person (
    id INT NOT NULL AUTO_INCREMENT,
    type ENUM('student', 'staff', 'guardian') NOT NULL,
    first_name CHAR(30) NOT NULL,
    last_name CHAR(30) NOT NULL,
    gender ENUM('m', 'f') NOT NULL,
    dob VARCHAR(30) NOT NULL,
    PRIMARY KEY (id)
);

学生表：

CREATE TABLE student (
    id INT NOT NULL AUTO_INCREMENT,
    person_id INT NOT NULL,
    primary_guardian INT NOT NULL,
    secondary_guardian INT,
    join_date VARCHAR(30) NOT NULL,  
    status ENUM('current', 'graduated', 'expelled', 'other') NOT NULL,
    tutor_group VARCHAR(30) NOT NULL,
    year_group VARCHAR(30) NOT NULL,
    PRIMARY KEY (id),
    FOREIGN KEY (person_id) REFERENCES person(id) ON DELETE CASCADE,
    FOREIGN KEY (primary_guardian) REFERENCES guardian(id),
    FOREIGN KEY (secondary_guardian) REFERENCES guardian(id),
    FOREIGN KEY (tutor_group) REFERENCES tutor_group(name),
    FOREIGN KEY (year_group) REFERENCES year_group(name)
);

事故表：

CREATE TABLE incident (
    id INT NOT NULL AUTO_INCREMENT,
    student INT NOT NULL,
    staff INT NOT NULL,
    guardian INT NOT NULL,
    sent_home BOOLEAN NOT NULL,
    illness_type VARCHAR(255) NOT NULL,
    action_taken VARCHAR(255) NOT NULL,
    incident_date DATETIME NOT NULL,
    PRIMARY KEY (id),
    FOREIGN KEY (student) REFERENCES student(id),
    FOREIGN KEY (staff) REFERENCES staff(id),
    FOREIGN KEY (guardian) REFERENCES guardian(id)
);

我想要选择的是第9年每个学生的名字，姓氏和事件数量。

这是我对查询的最佳尝试：

SELECT p.first_name, p.last_name, COUNT(i.student)
FROM person p, student s  LEFT JOIN incident i ON s.id = i.student 
WHERE p.id = s.person_id AND s.year_group LIKE "%Year 9%";

然而，它忽略了任何没有我不想要的事件的学生 - 他们应该被显示但是数量为0.如果我删除了左连接和计数，那么我得到了所有学生，正如我所期望的那样。

我可能误解了左连接，但我认为应该这样做，基本上我正在尝试做什么？

感谢您的帮助，

亚当

Answer 1

你做的很好，你只是错过了小组的条款

SELECT p.first_name, p.last_name, COUNT(i.student)
FROM person p, student s  LEFT JOIN incident i ON s.id = i.student 
WHERE p.id = s.person_id AND s.year_group LIKE "%Year 9%"
GROUP BY p.first_name, p.last_name;

这是一些测试数据

insert into person values(1, 'student', 'Alice', 'Foo', 'f','1970-01-01');
insert into person values(2, 'student', 'Bob', 'Bar', 'm','1970-01-01');

insert into student values(1,1,0,0,'', 'current','','Year 9');
insert into student values(2,2,0,0,'', 'current','','Year 9');

insert into incident values(1,1,0,0,0,'flu','chicken soup', '2008-01-08');

以下是添加了该组的查询输出：

+------------+-----------+------------------+
| first_name | last_name | COUNT(i.student) |
+------------+-----------+------------------+
| Alice      | Foo       |                1 |
| Bob        | Bar       |                0 |
+------------+-----------+------------------+

您可以通过从where子句创建join子句并对person id进行分组来进一步清理查询：

SELECT p.first_name, p.last_name, COUNT(i.student)
FROM person p
INNER JOIN student s ON(p.id = s.person_id)
LEFT JOIN incident i ON(s.id = i.student)
WHERE s.year_group LIKE "%Year 9%"
GROUP BY p.id;

Answer 2

或者，您可以使用 LEFT JOIN 相关子查询“>相关子查询：

SELECT
  p.first_name
  , p.last_name
  , (SELECT COUNT(*) FROM incident i WHERE i.student = s.id) 
FROM
  person p JOIN student s on s.person_id = p.id
WHERE
  s.year_group LIKE "%Year 9%"

Answer 3

你开始使用没有分组的计数，而你正在混合“在哪里”和“在...上”连接的语法。 试试这个：

SELECT p.first_name, p.last_name, COUNT(i.student)
FROM person p
JOIN student s on p.id = s.person
LEFT JOIN incident i ON s.id = i.student 
WHERE s.year_group LIKE "%Year 9%"
GROUP BY P.id;

Answer 4

这不是你要找的左外连接吗？我的术语可能会混淆了吗？不会是第一次。但Aron的回答是可行的。