打印从列表的y元素中选择的x不同对象的所有组合

Question

例如，52张扑克手中的5张卡= 2598960组合。
我如何实际显示所有这些组合？

查找数字的代码很容易：

def binomial_coef(total,subset)
  factorial(total) / (factorial(subset) * factorial(total - subset))
end

def factorial(n)
  n.downto(1).inject(:*)
end

# different 5 card poker hand combinations
cards = 52
hand_number = 5

puts binomial_coef(cards, hand_number)

关于打印所有实际组合的解决方案的想法吗？
例如：

1,2,3,4,5
1,2,3,4,6
等等

甚至有助于开始。谢谢！

Answer 1

你需要 Array#combination

cards = (1..52).to_a
hand_number = 5
cards.combination(hand_number).to_a

=> [[1,2,3,4,5],[1,2,3,4,6],...]

Answer 2

(1..52).to_a.combination(5)

Answer 3

puts (1..52).to_a.combination(5).to_a.inspect