长按uitableview

Question

我想在一个上处理长期按 UITableViewCell 打印“快速访问菜单”。有人已经这样做了吗？

特别是手势认识 UITableView?

Answer 1

首先将长按手势识别器添加到表视图中：

UILongPressGestureRecognizer *lpgr = [[UILongPressGestureRecognizer alloc] 
  initWithTarget:self action:@selector(handleLongPress:)];
lpgr.minimumPressDuration = 2.0; //seconds
lpgr.delegate = self;
[self.myTableView addGestureRecognizer:lpgr];
[lpgr release];

然后在手势处理程序中：

-(void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer
{
    CGPoint p = [gestureRecognizer locationInView:self.myTableView];

    NSIndexPath *indexPath = [self.myTableView indexPathForRowAtPoint:p];
    if (indexPath == nil) {
        NSLog(@"long press on table view but not on a row");
    } else if (gestureRecognizer.state == UIGestureRecognizerStateBegan) {
        NSLog(@"long press on table view at row %ld", indexPath.row);
    } else {
        NSLog(@"gestureRecognizer.state = %ld", gestureRecognizer.state);
    }
}

您必须小心这样 handleLongPress 可能会多次开火（这是由于手势识别器状态的变化引起的）。

Answer 2

我已经使用了Anna-Karenina的答案，并且在一个非常严重的错误中效果很好。

如果您正在使用各节，则长期按照部分标题将为您按下该部分上的第一行提供错误的结果，我在下面添加了一个固定的版本（包括基于手势状态的虚拟呼叫的过滤， Anna-Karenina建议）。

- (IBAction)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer
{
    if (gestureRecognizer.state == UIGestureRecognizerStateBegan) {

        CGPoint p = [gestureRecognizer locationInView:self.tableView];

        NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:p];
        if (indexPath == nil) {
            NSLog(@"long press on table view but not on a row");
        } else {
            UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:indexPath];
            if (cell.isHighlighted) {
                NSLog(@"long press on table view at section %d row %d", indexPath.section, indexPath.row);
            }
        }
    }
}

Answer 3

这是结合Dawn Song的答案和Marmor的答案的澄清说明。

拖动长按手势识别器，然后将其放入您的表单元格中。它将跳到左侧列表的底部。

然后以连接按钮的方式连接手势识别器。

在动作处理程序中添加Marmor的代码

- (IBAction)handleLongPress:(UILongPressGestureRecognizer *)sender {
if (sender.state == UIGestureRecognizerStateBegan) {

    CGPoint p = [sender locationInView:self.tableView];

    NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:p];
    if (indexPath == nil) {
        NSLog(@"long press on table view but not on a row");
    } else {
        UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:indexPath];
        if (cell.isHighlighted) {
            NSLog(@"long press on table view at section %d row %d", indexPath.section, indexPath.row);
        }
    }
}

}

Answer 4

在Swift 5中的答案（Ricky在Swift中的回答延续）

添加 UIGestureRecognizerDelegate 向您的ViewController

 override func viewDidLoad() {
    super.viewDidLoad()

    //Long Press
    let longPressGesture = UILongPressGestureRecognizer(target: self, action: #selector(handleLongPress))
    longPressGesture.minimumPressDuration = 0.5
    longPressGesture.delegate = self
    self.tableView.addGestureRecognizer(longPressGesture)
 }

和功能：

@objc func handleLongPress(longPressGesture: UILongPressGestureRecognizer) {
    let p = longPressGesture.location(in: self.tableView)
    let indexPath = self.tableView.indexPathForRow(at: p)
    if indexPath == nil {
        print("Long press on table view, not row.")
    } else if longPressGesture.state == UIGestureRecognizer.State.began {
        print("Long press on row, at \(indexPath!.row)")
    }
}

Answer 5

如下所示，看起来更有效地将识别器直接添加到单元格中：

点击并保留桌面电视单元，然后

（滚动到底部的示例）

Answer 6

在Swift中回答：

添加委托 UIGestureRecognizerDelegate 到您的uitaiteViewController。

在uitaiteViewController中：

override func viewDidLoad() {
    super.viewDidLoad()

    let longPressGesture:UILongPressGestureRecognizer = UILongPressGestureRecognizer(target: self, action: "handleLongPress:")
    longPressGesture.minimumPressDuration = 1.0 // 1 second press
    longPressGesture.delegate = self
    self.tableView.addGestureRecognizer(longPressGesture)

}

和功能：

func handleLongPress(longPressGesture:UILongPressGestureRecognizer) {

    let p = longPressGesture.locationInView(self.tableView)
    let indexPath = self.tableView.indexPathForRowAtPoint(p)

    if indexPath == nil {
        print("Long press on table view, not row.")
    }
    else if (longPressGesture.state == UIGestureRecognizerState.Began) {
        print("Long press on row, at \(indexPath!.row)")
    }

}

Answer 7

我根据安娜·卡雷纳娜（Anna Karenina）的出色答案，在UitaiteView上汇总了一个小类。

像这样，您将拥有一种方便的委托方法，就像您在处理常规表视图时习惯一样。看看这个：

//  UITableView+LongPress.h

#import <UIKit/UIKit.h>

@protocol UITableViewDelegateLongPress;

@interface UITableView (LongPress) <UIGestureRecognizerDelegate>
@property(nonatomic,assign)   id <UITableViewDelegateLongPress>   delegate;
- (void)addLongPressRecognizer;
@end


@protocol UITableViewDelegateLongPress <UITableViewDelegate>
- (void)tableView:(UITableView *)tableView didRecognizeLongPressOnRowAtIndexPath:(NSIndexPath *)indexPath;
@end



//  UITableView+LongPress.m

#import "UITableView+LongPress.h"

@implementation UITableView (LongPress)
@dynamic delegate;

- (void)addLongPressRecognizer {
    UILongPressGestureRecognizer *lpgr = [[UILongPressGestureRecognizer alloc]
                                          initWithTarget:self action:@selector(handleLongPress:)];
    lpgr.minimumPressDuration = 1.2; //seconds
    lpgr.delegate = self;
    [self addGestureRecognizer:lpgr];
}


- (void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer
{
    CGPoint p = [gestureRecognizer locationInView:self];

    NSIndexPath *indexPath = [self indexPathForRowAtPoint:p];
    if (indexPath == nil) {
        NSLog(@"long press on table view but not on a row");
    }
    else {
        if (gestureRecognizer.state == UIGestureRecognizerStateBegan) {
            // I am not sure why I need to cast here. But it seems to be alright.
            [(id<UITableViewDelegateLongPress>)self.delegate tableView:self didRecognizeLongPressOnRowAtIndexPath:indexPath];
        }
    }
}

如果您想在uitaiteViewController中使用它，则可能需要子类并符合新协议。

它对我来说很好，希望它能帮助别人！

Answer 8

Swift 3答案，使用现代语法，结合了其他答案，并消除了不需要的代码。

override func viewDidLoad() {
    super.viewDidLoad()
    let recognizer = UILongPressGestureRecognizer(target: self, action: #selector(tablePressed))
    tableView.addGestureRecognizer(recognizer)
 }

@IBAction func tablePressed(_ recognizer: UILongPressGestureRecognizer) {
    let point = recognizer.location(in: tableView)

    guard recognizer.state == .began,
          let indexPath = tableView.indexPathForRow(at: point),
          let cell = tableView.cellForRow(at: indexPath),
          cell.isHighlighted
    else {
        return
    }

    // TODO
}

Answer 9

只需将UilongPressestureRecognizer添加到故事板中给定的原型单元格中，然后将手势拉到ViewController的.m文件中以创建一个动作方法。我像我说的那样做到了。

Answer 10

使用touchesbegan中的Uitouch Timestamp属性启动计时器或在触摸被解雇时停止该计时器