Try this syntax.
${'day'.$c.'_hours'} = $value;
题
I'd like to change this:
if ($week_day == "1")
{
$day1_hours = $value;
}
if ($week_day == "2")
{
$day2_hours = $value;
}
if ($week_day == "3")
{
$day3_hours = $value;
}
if ($week_day == "4")
{
$day4_hours = $value;
}
if ($week_day == "5")
{
$day5_hours = $value;
}
if ($week_day == "6")
{
$day6_hours = $value;
}
if ($week_day == "7")
{
$day7_hours = $value;
}
}
Into something more readable, like a for loop, or whatever other suggestions you all may have.
I tried to do:
for ($c=1; $c<8, $c++)
{
if ($week_day == $c)
{
$day".$c."_hours = $value;
}
}
But I know that is nowhere near correct, and I have no idea how to insert another variable within a variable.
Any help is appreciated!
解决方案
Try this syntax.
${'day'.$c.'_hours'} = $value;
其他提示
Try this
$hours[$week_day] = $value
Something like this
$week_day = 3;
$value = "hi";
${"day" . $week_day . "_hours"} = $value;
echo $day3_hours;
My interpretation.
$week = 7;
$day = array();
for($i=1; $i<=7; $i++){
$day[$i]['hours'] = $value;
}
You can declare the numbers of weeks you want and to pull the data you can do something like this:
echo $day[1]['hours']