I have a file extension, I got it in this way:

fileName, fileExtension = os.path.splitext(abspath)

now I need my file extension to became a pattern, something like '*.fileExtension', included the quote characters. I should use it in a fnmatch like this:

if fnmatch.fnmatch(name, pattern)

any idea?

有帮助吗?

解决方案

Use string concatenation:

pattern = '*' + fileExtension

or use string formatting:

pattern = '*{}'.format(fileExtension)

or

pattern = '*%s' % fileExtension
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