部分应用递归函数

Question

def mainCaller() = { 
  val name = "xyz"
  someList.foreach { u:Map => foo(name, u) }
}

def foo(name:String)(map:Map): Unit = {
  //match case....
  //recursive call to foo in each case where name remains same, but map changes
}

我如何将foo作为部分应用功能写，我不必在每个递归电话中传递名称，只需呼叫 foo(map1)?

Answer 1

两个选项：

def foo(name:String)(map:Map): Unit = {
    val bar = foo(name)_
    //match case...
    // case 1:
    bar(x)

    // case 2:
    bar(y)
}

或者：

def foo(name:String): Map => Unit = {
    def bar(map: Map): Unit = {
        //match case...
        // case 1:
        bar(x)

        // case 2:
        bar(y)
    }
    bar
}