这个HQL有什么问题？ ＆＃8220;没有节点的数据类型＆＃8221;

StackOverflow https://stackoverflow.com/questions/1012408

  •  06-07-2019
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题 

session.createQuery("Select attribute from GoodsSection tgs " +
    "join gs.ascendants ags join ags.attributes attribute " +
    "where attribute.outerId = :outerId and tgs = :section ")
.setString("outerId", pOuterId)
.setEntity("section", section)
.setMaxResults(1)
.uniqueResult();

对我来说很好，但结果是

java.lang.IllegalStateException: No data type for node: org.hibernate.hql.ast.tree.IdentNode 
 \-[IDENT] IdentNode: 'attribute' {originalText=attribute}

    at org.hibernate.hql.ast.tree.SelectClause.initializeExplicitSelectClause(SelectClause.java:145)
    at org.hibernate.hql.ast.HqlSqlWalker.useSelectClause(HqlSqlWalker.java:705)
    at org.hibernate.hql.ast.HqlSqlWalker.processQuery(HqlSqlWalker.java:529)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:645)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229)

为什么呢？怎么了？

有帮助吗？

解决方案

您尚未定义“gs”别名。你只有“ags”和“tgs”。

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