tagcloud中标签的字体大小的公式是什么？

Question

我有一个标签云，我需要知道如何更改最常用的标签的字体大小。

我需要设置一个最小尺寸和最大尺寸。

Answer 1

您可以对与最大标签相关的特定标签相关的项目数量进行线性或对数评估，将其乘以最小字体和最大字体尺寸之间的差，然后将其添加到最小字体大小中。例如，伪代码中的数学可能是：

let min = 12, max = 24
for each tag
    font = (items / items in biggest tag) * (max - min) + min

Answer 2

为了使 @delan的答案更加清楚，我用我熟悉的语言创建了一些示例。

JavaScript中的示例

var tags =
[
    { Name: "c#", Uses: 100 },
    { Name: ".net", Uses: 75 },
    { Name: "typescript", Uses: 50 },
    { Name: "lua", Uses: 50 },
    { Name: "javascript", Uses: 25 },
    { Name: "jquery", Uses: 1 },
    { Name: "c++", Uses: 0 },
];

var max = 100; // Should be computed
var min = 0;   // Should be computed

var fontMin = 10;
var fontMax = 20;

for (var i in tags)
{
    var tag = tags[i];

    var size = tag.Uses == min ? fontMin
        : (tag.Uses / max) * (fontMax - fontMin) + fontMin;
}

C＃中的示例

var tags = new List<Tag>
{
    new Tag { Name = "c#", Uses = 100 },
    new Tag { Name = ".net", Uses = 75 },
    new Tag { Name = "typescript", Uses = 50 },
    new Tag { Name = "lua", Uses = 50 },
    new Tag { Name = "javascript", Uses = 25 },
    new Tag { Name = "jquery", Uses = 5 },
    new Tag { Name = "c++", Uses = 5 },
};

int max = tags.Max(o => o.Uses);
int min = tags.Min(o => o.Uses);

double fontMax = 20;
double fontMin = 10;

foreach (var tag in tags)
{
    double size = tag.Uses == min ? fontMin
        : (tag.Uses / (double)max) * (fontMax - fontMin) + fontMin;
}

Answer 3

尝试：

<div data-i2="fontSize:[10,30]">
    <span data-i2="rate:1">A</span>
    <span data-i2="rate:4">B</span>
    <span data-i2="rate:7">C</span>
    <span data-i2="rate:12">G</span>
    <span data-i2="rate:5">H</span>
</div>

然后

i2.emph();

http://jsfiddle.net/euac5/1/

Answer 4

我想到了：

max_word_count = 412  # should count from list
min_word_count = 44   # should count from list
difference = max_word_count - min_word_count
min_weight = 99 / difference * min_word_count

for each tag
    weight = 99 / difference * this_word_count - min_weight + 1

这给了我1到100之间的称重。它对我很好地工作 znaci.net/arhiv.

免责声明：我不擅长数学。