on Childview上的onlongClicklistener在parentview上禁用OnTouchListener

Question

我有一个 AbsoluteLayout 有一个 OnTouchListener. 。在这个布局内部有一个小得多 LinearLayout 动态定位。 OnTouchListener按预期工作。

现在，当我添加一个 LongClickListener 对我的 LinearLayout. 。那禁用了我 OnTouchListener 如果触摸达到了 LinearLayout, ，但是如果 LinearLayout 曾是 不是 受到触摸的打击。

我的听众：

// listener on parent (AbsoluteLayout)
setOnTouchListener(new OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        Log.e("LOOOOGING");
        mLinearLayout.getHitRect(mNoteRect);
        mNoteRect.left += mX;
        mNoteRect.top += mY;
        mNoteRect.right = mNoteRect.left + mLinearLayout.getWidth();
        mNoteRect.bottom = mNoteRect.top + mLinearLayout.getHeight();
        if (mNoteRect.contains((int) event.getX(), (int) event.getY())) {
            if (event.getAction() == MotionEvent.ACTION_DOWN) {
                mStartX = (int) event.getX() - mNoteRect.left;
                mStartY = (int) event.getY() - mNoteRect.top;
                return true;
            }
            mX = (int) event.getX() - mStartX;
            mY = (int) event.getY() - mStartY;

            setPadding(mX, mY, 0, 0);
            return true;
        }
        return false;
    }
});

// listener on child (LinearLayout)
mLinearLayout.setOnLongClickListener(new OnLongClickListener() {
    @Override
    public boolean onLongClick(View v) {
        // do something...
        return true;
    }
});

我如何将触摸委托给 LinearLayout 在哪里 OnLongClickListener 是否注册给父母？

Answer 1

我必须在我的ontouchlistener内部建立自己的长智能行为

private Handler mLongPressHandler = new Handler();

public final Runnable mDoLongPress = new Runnable() {
    public void run() {
        // do something
    }
};

setOnTouchListener(new OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        mLinearLayout.getHitRect(mNoteRect);
        mNoteRect.left += mX;
        mNoteRect.top += mY;
        mNoteRect.right = mNoteRect.left + mLinearLayout.getWidth();
        mNoteRect.bottom = mNoteRect.top + mLinearLayout.getHeight();
        if (mNoteRect.contains((int) event.getX(), (int) event.getY())) {
            if (event.getAction() == MotionEvent.ACTION_DOWN) {
                mStartRawX = (int) event.getX();
                mStartRawY = (int) event.getY();
                mStartX = mStartRawX - mNoteRect.left;
                mStartY = mStartRawY - mNoteRect.top;
                mLongPressHandler.postDelayed(mDoLongPress, 1000);
                return true;
            }
            mX = (int) event.getX() - mStartX;
            mY = (int) event.getY() - mStartY;
            if (event.getAction() == MotionEvent.ACTION_MOVE) {
                if ((mStartRawX + 10 < (int) event.getX() || mStartRawX - 10 > (int) event.getX())
                        || (mStartRawY + 10 < (int) event.getY() || mStartRawY - 10 > (int) event.getY())) {
                    mLongPressHandler.removeCallbacks(mDoLongPress);
                }
            }
            if (event.getAction() == MotionEvent.ACTION_UP) {
                mLongPressHandler.removeCallbacks(mDoLongPress);
            }

            setPadding(mX, mY, 0, 0);
            return true;
        }
        return false;
    }
});

Answer 2

你尝试过这样的事情吗？

   // listener on child (LinearLayout)
mLinearLayout.setOnLongClickListener(new OnLongClickListener() {
    @Override
    public boolean onLongClick(View v) {
        AbsoluteLayout.requestFocus();
        //do something else
        return true;
    }
});

从我阅读的内容来看，触摸等同于获得重点。 （（处理UI活动)

编辑：检查“绝对层”文档，也许这可能会有所帮助： DispatchTouchEvent（MotionEvent EV）. 。尝试玩它，听起来像是从 公共布尔隆克利克（查看V） 有帮助

将触摸屏运动事件传递到目标视图，或者如果是目标，则此视图。

Answer 3

Maragues从OnlongClick（）发送DispatchTouchEvent（）的想法似乎很有希望，但是您必须构建一个事件对象，以发送到DispatchTouchTouchevent（）以模仿OnlongClicklistener所消耗的事件。

我四处翻转以拦截父母视图中的触摸事件，然后将其转发到孩子的视野。我对父视图进行了分类，然后添加了此方法：

@Override
public boolean onInterceptTouchEvent(MotionEvent event) {
    // this allows us to catch touch events on the list view if a child button is in the same location, then pass them on to child buttons so they can use them, too
    // we don't have to worry about move events because currently none of the child buttons use them
    int touchX = Math.round(event.getX());
    int touchY = Math.round(event.getY());
    Rect touchRect = new Rect(touchX, touchY, touchX, touchY);
    Log.d("onInterceptTouchEvent", "got touch at " + touchRect);
    switch (event.getAction() & MotionEvent.ACTION_MASK) {
        case MotionEvent.ACTION_DOWN:
        case MotionEvent.ACTION_UP:
        case MotionEvent.ACTION_CANCEL:
            for (View cell : ViewUtils.getSubviews(this)) {
                int cellX = Math.round(cell.getX());
                int cellY = Math.round(cell.getY());
                Rect cellRect = new Rect(cellX, cellY, cellX + cell.getWidth(), cellY + cell.getHeight());
                if (Rect.intersects(touchRect, cellRect)) {
                    for (View button : ViewUtils.getSubviews((ViewGroup) cell)) {
                        if (button instanceof ImageButton) {
                            int buttonX = Math.round(button.getX()) + cellX;
                            int buttonY = Math.round(button.getY()) + cellY;
                            Rect buttonRect = new Rect(buttonX, buttonY, buttonX + button.getWidth(), buttonY + button.getHeight());
                            Log.d("onInterceptTouchEvent", "found button at " + buttonRect);
                            if (Rect.intersects(touchRect, buttonRect)) {
                                Log.d("onInterceptTouchEvent", "forward touch to button");
                                button.dispatchTouchEvent(event);
                                break;
                            }
                        }
                    }
                    break;
                }
            }
            break;
    }
    return true;
}

就我而言，父视图是listView，孩子的视图是表单元格内部的imageButtons。因此，该代码通过表单元格，然后是每个单元格中的按钮迭代，以找到与触摸位置相匹配的按钮，并将触摸触摸到该按钮。我的按钮都是使用OnClickListener或OnlongClickListener的所有imageButtons，因此我不转发Action_Move事件，但是您可以在需要时。

这是上面使用的GetSubViews（）方法：

public static ArrayList<View> getSubviews(ViewGroup viewGroup) {
    ArrayList<View> subviews = new ArrayList<View>();
    for (int i=0; i<viewGroup.getChildCount(); i++) {
        subviews.add(viewGroup.getChildAt(i));
    }
    return subviews;
}

更新：更简单的版本

上面的代码应适用于在父视图上接收触摸的特定情况，并在子视图上进行长时间点击。但是我发现这不支持儿童视图中的常规点击。我认为这与OninterceptTouchevent（）处理Action_down事件的方式与处理其他事件的方式不同。这 此方法的文档 很困惑。

但是，这是一种更简单的方法，应该支持父母或子女视图中的各种触摸和点击事件。如上所述，这需要子分类。它还需要直接在该类中设置OnTouch方法，而不是在另一类中使用SetOntOntouchListener（）：

@Override
public boolean onInterceptTouchEvent(MotionEvent event) {
    this.onTouch(this, event); // send the touch to the onTouch method below
    return false; // then let the touch proceed to child buttons
    // return true = this method and this view's onTouch receives events; return false = this method and children's onTouch receive events; remove this method = only children's onTouch receive events
}

@Override
public boolean onTouch(View v, MotionEvent event) {
    // work with this touch event here
    return false; // then let the touch continue to other applicable views
    // return true = only this view receives events; return false = this view and other applicable views receive events
}