-
04-10-2019 - |
题
我正在尝试制作一个重新值的函数。
在我的功能中,我有这个脚本:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12 -- going to be a variable
)
回报是这样的:
http://img59.imageshack.us/img59/6733/tablei.gif
现在我想回来 row 3
coze有一个 1
在ROUTER RERATER -MUT中
我该怎么办?我试图用2做 With
但是Oracle尚未支持2。
解决方案 2
我的解决方案:
WITH t_new AS
(
-- Alles durch gehen und
SELECT PersIDOLD, PersIDNEW, RightsMUT, SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM LUTAXKT.HILFSTABELLE1UMSETZUNG h1
--WHERE h1.updateflag = 0
)
)
SELECT PersIDNEW, RightsMUT
FROM t_new
WHERE RightsMUT = 1 and
grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12
)
其他提示
让我尝试猜测 - 请检查以下内容是否给您您的需求:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE PersIDNEW = 12 AND RightsMUT = 1
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